-2^6-(6)^2= -100. Hope this helps have a great day. :)
2 times the amount that the army is to the basket ball hoop
Required equation is y - y1 = m(x - x1); where m = 4 and (x1, y1) = (4, -4)
y - (-4) = 4(x - 4)
y + 4 = 4(x - 4)
We want to see how much the population of goats grows each year. We will see that the correct option is c: 17%.
<h3>
Exponential growth of populations</h3>
We know that:
- The initial number of goats is 1,500.
- After 11 years, the population is 8,400.
The population can be modeled with an exponential equation as:
P(t) = A*(1 + r)^t
Where:
- A is the initial population.
- r is what we want to find, it depends on how much the population increases.
- t is the time in years.
So we have:
P(t) = 1500*(1 + r)^t
And we know that after 11 years the population is 8,400, so we have:
P(11) = 1500*(1 + r)^11 = 8400
Now we can solve this for r:
(1 + r)^11 = 8400/1500 = 5.6
(1 + r) = (5.6)^(1/11) = 1.17
r = 1.17 - 1 = 0.17
r = 0.17
To get it in percentage form, you just need to multiply it by 100%
0.17*100% = 17%
This means that the population increases a 17% each year, so the correct option is c.
If you want to learn more about exponential growth, you can read:
brainly.com/question/13223520
0.91 isnt the same as 0.081
