What is the circumference of a circle with a radius of 7 centimeters? Use 3.14 for S.

Motorola used the normal distribution to determine the probability of defects and the number of defects expected in a production

Lena [83]

The question supplied is incomplete :

The x parameters aren't given ; "Units with weights less than or greater than ounces will be classified as defects"

Assume the unit weights Given are ;

Units with weights less than 10.8 or greater than 11.2 ounces will be classified as defects

Just follow the procedure in the solution for any value of unit weight interval given.

Answer:

0.3173

Step-by-step explanation:

Mean weight, m = 11 ounces

Standard deviation, s = 0.2 ounces

Find the Zscore for each unit weight :

Z = (x - mean) / standard deviation

P(x < 10.8) :

Z = (10.8 - 11) / 0.2 = - 1

P(Z < - 1) = 0.15866

P(x > 11.2) :

Z = (11.2 - 11) / 0.2 = 1

P(Z > 1) = 0.84134

P(x < 11.2) - P(x < 10.8) = 1 - (P(Z < 1) - P(Z < - 1)) = 1 - 1 - (0.84134 - 0.15866) = 1 - 0.68268 = 0.31732

Hence, Probability of a defect is 0.3173

7 0

3 years ago

element x is a radioactive isotope such that every 32 years, its mass decreases by half. given that the initial mass of the samp

VashaNatasha [74]

Answer:

the answer is 31.9 years

Step-by-step explanation:

initial mass, $M_{0}$ = 150 gram

half life, $t_{half\hspace{0.1cm}life}$ = 32 years

new mass = half of initial mass = M = 0.5 $M_{0}$

formula , M = $M_{0}$ $e^{\frac{\ln\frac{1}{2}}{t_{half} }\times x }$ where x is the number of years required.

therefore 0.5 $M_{0}$ = $M_{0}$ $e^{\frac{\ln\frac{1}{2}}{t_{half} }\times x } = M_{0} e^{-0.0217x}$

therefore -0.0217 x = $\ln{0.5} = -0.693$

therefore x = $\frac{-0.693}{-0.0217}$ = 31.942

8 0

3 years ago

suppose Tomas buys a total of 30 baseball and football cards in week 5 . how many of each would he have to buy to keep the same

Charra [1.4K]

Answer:

18 baseball cards
12 football cards

Step-by-step explanation:

The only relationship shown in the table is in week 1, where the ratio of baseball to football cards is ...

baseball : football = 9 : 6

In week 1, the total of these numbers is 15. You want the total in week 5 to be 30, double the total in week 1. So, Thomas needs to purchase double the numbers he purchased in week 1:

18 baseball cards
12 football cards

_____

<em>Comment on the attachment</em>

This table came from another question you posted, a question with no content other than the table. The blue numbers are blanks in the original table that have been filled in so as to keep the same 3:2 proportion in each week. They appear to have no bearing on this question.