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ANTONII [103]
3 years ago
12

Find the complete solution of the linear system, or show that it is inconsistent. (If the system has infinitely many solutions,

express your answer in terms of t, where x = x(t), y = y(t), and z = t. If there is no solution, enter NO SOLUTION.)
x − y + 2z = 1
3x + y + 5z = 19
2x − y − 2z = −17
(x, y, z) = ( ________ ) ...?
Mathematics
2 answers:
d1i1m1o1n [39]3 years ago
8 0

Answer:

The solution of equation is :(-2,5,4)

Step-by-step explanation:

x - y + 2z = 1

..[1]

3x + y + 5z = 19  ..[2]

2x - y - 2z = -17 ...[3]

Putting value of y from [1] in [2]and [3]

y = x+ 2z -1

3x + (x+ 2z -1) + 5z = 19  

4x + 7z = 20  ...[4]

2x - (x+ 2z -1) - 2z = -17

x - 4z = -18   ...[5]

Solving equation [4] and [5] by substitution:

Putting values of x from [5] in [4]

x = 4z -18

4(4z -18) + 7z = 20  ...[4]

16z - 72+ 7z =20

23z = 92

z = 4

x = 4\times \frac{92}{23}-18=-2

y = (-2)+ 2\frac{92}{23} -1=5

(x,y,z)= (5.-2,4)

The solution of equation is :(-2,5,4)

ad-work [718]3 years ago
5 0
<span>x − y + 2z = 1
3x + y + 5z = 19
2x − y − 2z = −17

-3x+3y-6z=-3
</span>3x + y + 5z = 19

4y-z=16 (1)

-2x+2y-4z=-2
<span>2x − y − 2z = −17

y-6z=-19  (2)

</span>4y-z=16  (1)
y-6z=-19 (2)

4y-z=16 
-4y+24z=76

23z=92
z=4

y-6z=-19
y-6×4=-19
y-24=-19
y=24-19
y=5

<span>x − y + 2z = 1
</span>x-5+2×4=1
x-5+8=1
x+3=1
x=-2

(x,y,z)=(-2,5,4)
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Which of the following equations represents the perpendicular bisector of WX graphed below?
kotykmax [81]
The coordinates of the 2 given points are W(-5, 2), and X(5, -4).

First, we find the midpoint M using the midpoint formula:

\displaystyle{ M_{WX}= (\frac{x_1+x_2}{2},  \frac{y_1+y_2}{2} )=  (\frac{-5+5}{2},  \frac{2+(-4)}{2} )=(0, -1).

Nex, we find the slope of the line containing M, perpendicular to WX. We know that if m and n are the slopes of 2 parallel lines, then mn=-1.

The slope of WX is \displaystyle{ m= \frac{y_2-y_1}{x_2-x_1}= \frac{2-(-4)}{-5-5}= \frac{6}{-10}= -\frac{3}{5}.

Thus, the slope n of the perpendicular line is \displaystyle{  \frac{5}{3}.

The equation of the line with slope \displaystyle{ n= \frac{5}{3} containing the point M(0, -1) is given by:

\displaystyle{ y-(-1)=\frac{5}{3}(x-0)

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GaryK [48]

Answer:

  • The two solutions are:           x=\frac{1}{2}+/-\frac{\sqrt{7} }{2}

  • The next and every step are below.

Explanation:

1. -3=-2x^2+2x    : Given (addition property / add - 3 to both sides)

2. -3 = - 2(x^2-x)    : Given (commom factor - 2)

3. -3-1/2=-2(x^2-x+1/4)

    To obtain the perfect square it was added the square of half of the coefficient of x: (1/2)² = 1/4, inside the parenthesis.

Since, the terms inside the parentthesis are multiplied by - 2, you have to add - 2 (1/4) = - 1/2 to the left side of the equation.

4. Now, you have that the trinomial x² - x + 1/4 is a square perfect trinomial which is factored as (x - 1/2)² and get the expression:

-7/2=-2(x-1/2)^2

5. Divide both sides by - 2 to get the next expression:

-7/4=(x-1/2)^2

6. The last step is to extract squere root from both sides of the equality:

(x-1/2)=+/-\sqrt{\frac{7}{4}}\\ \\ x-1/2=+/-\frac{\sqrt{7} }{2}\\ \\ x=\frac{1}{2}+/-\frac{\sqrt{7} }{2}

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Answer

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Step-by-step explanation:

Have a good day :)

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