Answer: Reject the eight- ounces claim.
Step-by-step explanation:
For left tailed test , On a normal curve the rejection area lies on the left side of the critical value.
It means that if the observed z-value is less than the critical value then it will fall into the rejection region other wise not.
As per given ,
Objective : A coffee-dispensing machine is supposed to deliver eight ounces of liquid or less.
Then ,
, since alternative hypothesis is left-tailed thus the test is an left-tailed test.
the critical value for z for a one-tailed test with the tail in the left end is -1.645 and the obtained value is -1.87.
Clearly , -1.87 < -1.645
⇒ -1.87 falls under rejection region.
⇒ Decision : Reject null hypothesis.
i.e. we reject the eight- ounces claim.
Answer:
fraction which has a terminating decimal as its decimal expansion is:
1/5
Step-by-step explanation:
We are given 4 fractions:
1/3 , 1/5 , 1/7 and 1/9
We have to find which fraction has terminating decimal.
1/3 = 0.33333...
1/5 = 0.2
1/7 = 0.142857142857...
1/9 =0.11111.....
Hence, fraction which has a terminating decimal as its decimal expansion is:
1/5
Well if pi is referred to as 3.14 then the distance around the garden would be 314.
The formula for Circumfrence is pi times diameter, so 3.14 times 100 = 314 (circumfrence)
Two fractions equivalent to each: Just divide or multiply both top AND bottom by the same number.<span>
5/6: 10/12 OR 15/18
15/30: 5/10 OR 1/2
45/60: 8/12 OR 4/6
Rewrite each pair or fractions with common denominator: Find the difference between the two bottom numbers, and multiply top and bottom number.
5/8 and 3/4: 4X2=8, 3X2=6. So, 5/8 and 6/8.
2/5 and 1/2: 2/5 and 2.5/5
9/9 and 5/7: 9/9 and ~5.7/9
Rewrite each in simple form: Find greatest common factor and divide.
9/54: 1/6
20/40: 1/2
100/110: 10/11
Are these fractions equivalent?
No. 5/1 and 5/5 are, because they are both 5 wholes. 1/5 is not because it is a fifth of a whole.
In what situation can you use multiplication to find equivalent fractions?
I'm sorry but I do not understand this question.
</span>Source(s):<span>I hope I helped, seeing as I have graduated with a math degree.</span>
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