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Anastasy [175]
3 years ago
5

A student studying for a vocabulary test knows the meanings of 16 words from a list of 26 words. If the test contains 10 words f

rom the study list, what is the probability that at least 8 of the words on the test are words that the student knows? (Round your answer to three decimal places.)
Mathematics
1 answer:
gayaneshka [121]3 years ago
4 0
To get the probability that at least 8 of the words on the test are words that students know we need to do the following calculations.

<span>=[C(16,8)*C(10,2) + C(16,9)*C(10,1) + C(16,10)*C(10,0)] / C(26,10)
</span>
=0.132 
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Answer:

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Which 2 teams scored a total of 100 points, red has 29 points, yellow has 38 points, Green has 41 points, blue has 76 points ora
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Answer:

Blue and Black

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single die is rolled twice. Find the probability of rolling an oddodd number the first time and a number greater than 33 the sec
givi [52]

Answer:

\frac{1}{4}

Step-by-step explanation:

A single die is rolled twice, we have to find the probability of rolling an odd number in first throw and a number greater than 3 in the second throw.

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A die has total 6 possible outcomes, out of which 3 are odd numbers i.e. 1,3 and 5

So, total number of possible outcomes = 6

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Probability is defined as the ratio of favorable outcomes to total number of outcomes. So,

The probability of rolling an odd number would be = \frac{3}{6} = \frac{1}{2}

b) Rolling a number greater than 3 in second throw

Here again total possible outcomes = 6

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So,

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These two events(rolls) are independent of each other, so the overall probability of both events occurring would be the product of individual probabilities.

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Probability of rolling an odd number the first time and a number greater than 3 the second time = \frac{1}{2} \times \frac{1}{2} = \frac{1}{4}

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