Ask question

Ask question

All categories

2 years ago

5

A student studying for a vocabulary test knows the meanings of 16 words from a list of 26 words. If the test contains 10 words f

rom the study list, what is the probability that at least 8 of the words on the test are words that the student knows? (Round your answer to three decimal places.)

1 answer:

gayaneshka [121]2 years ago

4 0

To get the probability that at least 8 of the words on the test are words that students know we need to do the following calculations.

<span>=[C(16,8)*C(10,2) + C(16,9)*C(10,1) + C(16,10)*C(10,0)] / C(26,10)
</span>
=0.132

You might be interested in

Find the slope of the line that passes through (8,9) and (1, 3).

Finger [1]

Answer:

m=6/7

Step-by-step explanation:

3 0

1 year ago

Read 2 more answers

Please help me solve this question will give you braisnlt !

Hoochie [10]

Answer:

fdsfada

Step-by-step explanation:

dsfafdsf

5 0

2 years ago

Can some one explain and help me and answer it

brilliants [131]

Answer

Sal spent 43 minutes jogging per day last week.

Elena spent 45 minutes jogging per day last week.

Step-by-step

Part 1: Find the number of minutes Sal jogged.

1. Find the number of minutes out of the week that were spent jogging.

240 - 25 = 215

Sal spent 215 minutes jogging.

2. Find the number of minutes per day he spent jogging.

215 / 5 = 43

Sal spent 43 minutes jogging per day last week.

Part 2: Find the number of minutes Elena jogged.

1. Find the number of minutes out of the week that were spent jogging.

300 - 15(5) = 300 - 75 = 225

Elena spent 225 minutes jogging.

2. Find the number of minutes per day she spent jogging.

225 / 5 = 45

Elena spent 45 minutes jogging per day last week.

4 0

3 years ago

Solve for a a^2+17=42?

grandymaker [24]

We are given the following equation:

$a^2+17=42$

Subtract both sides by 17

$a^2=25$

Take the positive/negative square root of both sides

$a=\pm5$

This should be your answer. Let me know if you have any questions, thanks!

6 0

2 years ago

Find the area of the composite figure.

Roman55 [17]

Answer:

The Area of the composite figure would be 76.26 in^2

Step-by-step explanation:

<u>According to the Figure Given:</u>

Total Horizontal Distance = 14 in

Length = 6 in

<u>To Find :</u>

The Area of the composite figure

<u>Solution:</u>

Firstly we need to find the area of Rectangular part.

So We know that,

$\boxed{ \rm \: Area \: of \: Rectangle = Length×Breadth}$

Here, Length is 6 in but the breadth is unknown.

To Find out the breadth, we’ll use this formula:

$\boxed{\rm \: Breadth = total \: distance - Radius}$

According to the Figure, we can see one side of a rectangle and radius of the circle are common, hence,

$\longrightarrow\rm \: Length \: of \: the \: circle = Radius$

Since Length = 6 in ;

$\longrightarrow \rm \: 6 \: in = radius$

Hence Radius is 6 in.

So Substitute the value of Total distance and Radius:

Total Horizontal Distance= 14
Radius = 6

$\longrightarrow\rm \: Breadth = 14-6$

$\longrightarrow\rm \: Breadth = 8 \: in$

Hence, the Breadth is 8 in.

Then, Substitute the values of Length and Breadth in the formula of Rectangle :

Length = 6
Breadth = 8

$\longrightarrow\rm \: Area \: of \: Rectangle = 6 \times 8$

$\longrightarrow \rm \: Area \: of \: Rectangle = 48 \: in {}^{2}$

Then, We need to find the area of Quarter circle :

We know that,

$\boxed{\rm Area_{(Quarter \; Circle) } = \cfrac{\pi{r} {}^{2} }{4}}$

Now Substitute their values:

r = radius = 6
π = 3.14

$\longrightarrow\rm Area_{(Quarter \; Circle) } = \cfrac{3.14 \times 6 {}^{2} }{4}$

Solve it.

$\longrightarrow\rm Area_{(Quarter \; Circle) } = \cfrac{3.14 \times 36}{4}$

$\longrightarrow\rm Area_{(Quarter \; Circle) } = \cfrac{3.14 \times \cancel{{36} } \: ^{9} }{ \cancel4}$

$\longrightarrow\rm Area_{(Quarter \; Circle)} =3.14 \times 9$

$\longrightarrow\rm Area_{(Quarter \; Circle) } = 28.26 \: {in}^{2}$

Now we can Find out the total Area of composite figure:

We know that,

$\boxed{ \rm \: Area_{(Composite Figure)} =Area_{(rectangle)}+ Area_{ (Quarter Circle)}}$

So Substitute their values:

$\rm Area_{(rectangle)}$ = 48
$\rm Area_{(Quarter Circle)}$ = 28.26

$\longrightarrow \rm \: Area_{(Composite Figure)} =48 + 28 .26$

Solve it.

$\longrightarrow \rm \: Area_{(Composite Figure)} =\boxed{\tt 76.26 \:\rm in {}^{2}}$

Hence, the area of the composite figure would be 76.26 in² or 76.26 sq. in.

$\rule{225pt}{2pt}$

I hope this helps!

3 0

1 year ago