PLEASE HELP How can the area of this triangle be determined by forming a rectangle? Select from the drop-down menus to correctly
complete the statements. Copy and rotate the triangle and place it next to the existing triangle to form a rectangle. The length of the rectangle is (choose) 4,5,8,10 units. The width of the rectangle is (choose) 4,5,8,10 units. The area of the rectangle is (choose) 10,16,20,25 square units.
The area of the triangle is half the area of the rectangle, so the area of the triangle is (choose)
10,16,20,25
square units.
The area of the triangle is half the area of the rectangle, so the area of the triangle is (choose)
10,16,20,25
square units.
2 answers:
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Answer:
a) The expected value is given by:
and the variance is given by:
b)
And we can find this probability with the following Excel code:
=1-BINOM.DIST(25,50,0.4,TRUE)
And we got:
c) 1) Random sample (assumed)
2) np= 50*0.4= 20 >10
n(1-p) =50*0.6= 30>10
3) Independence (assumed)
Since the 3 conditions are satisfied we can use the normal approximation:
d)
e)
Step-by-step explanation:
Previous concepts
The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".
Let X the random variable of interest, on this case we now that:
The probability mass function for the Binomial distribution is given as:
Where (nCx) means combinatory and it's given by this formula:
Part a
The expected value is given by:
and the variance is given by:
Part b
For this case we want to find this probability:
And we can find this probability with the following Excel code:
=1-BINOM.DIST(25,50,0.4,TRUE)
And we got:
Part c
1) Random sample (assumed)
2) np= 50*0.4= 20 >10
n(1-p) =50*0.6= 30>10
3) Independence (assumed)
Since the 3 conditions are satisfied we can use the normal approximation:
Part d
We want this probability:
Part e
For this case we use the continuity correction and we have this: