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3 years ago

6

Tim answered all the questions on his math test but got 10 answers wrong. He received 4 points for every correct answer, and the

re was no penalty for wrong answers. His score was 76 points.
Write an equation to determine the total number of questions (q) on Tim's math test.

Find the total number of questions on his math test.

2 answers:

charle [14.2K]3 years ago

8 0

4x = 76
Where x is how many awnsers he got correct and 4 how many points each correct question awnsered.

Now you just have to isolate x by dividing both sides of the equation by 4

4x/4 = 76/4
x = 19

So he got 19 questions right and 10 awnsers wrong. In total there were 29 questions on his test

sweet [91]3 years ago

8 0

Answer:

q-10=76/4 29 questions

Step-by-step explanation:

khan

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Answer:

Add 6 each time.

Step-by-step explanation:

Figure 1 has 4 tiles.

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To go from figure 2 (10 tiles) to figure 3 (16 tiles), you added 6 tiles.

∴ the rule is to add 6 tiles each time.

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2 years ago

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Step-by-step explanation:

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3 years ago

Jane wishes to bake an apple pie for dessert. The baking instructions say that she should bake the pie in an oven at a constant

Viktor [21]

Answer:

Therefore $k= \frac{ln2 }{18}$ , A=184

Step-by-step explanation:

Given function is

$T(t)=230 -e^{-kt}$

where T(t) is the temperature in °C and t is time in minute and A and k are constants.

She noticed that after 18 minutes the temperature of the pie is 138°C

Putting T(t) =138°C and t= 18 minutes

$138=230 -Ae^{-k\times 18}$

$\Rightarrow -Ae^{-18k}=138-230$

$\Rightarrow Ae^{-18k}=92$ .....(1)

Again after 36 minutes it is 184°C

Putting T(t) =184°C and t= 36 minutes

$184=230-Ae^{-k\times 36}$

$\Rightarrow Ae^{-36k}=230-184$

$\Rightarrow Ae^{-36k}=46$ .......(2)

Dividing (2) by (1)

$\frac{Ae^{-36k}}{Ae^{-18k}}=\frac{46}{92}$

$\Rightarrow e^{-18k}=\frac{46}{92}$

Taking ln both sides

$ln e^{-18k}=ln\frac{46}{92}$

$\Rightarrow -18k =ln (\frac12)$

$\Rightarrow -18k= ln1-ln2$

$\Rightarrow k= \frac{ln2 }{18}$

Putting the value k in equation (1)

$Ae^{-18\frac{ln2}{18}}=92$

$\Rightarrow A e^{ln2^{-1}}=92$

$\Rightarrow A.2^{-1}=92$

$\Rightarrow \frac{A}{2}=92$

$\Rightarrow A= 92 \times 2$

⇒A= 184.

Therefore $k= \frac{ln2 }{18}$ , A=184

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3 years ago

Math. Help much appreciated

ella [17]

First of all, expand the left hand side:

$4x+4 - 7 < 3x + 5$

Sum like terms:

$4x -3 < 3x + 5$

Add 3 to both sides:

$4x < 3x + 8$

Subtract 3x from both sides:

$x < 8$

So this is the solution. Every number smaller than 8 (excluded) is part of the solution of this inequality.

4 0

2 years ago

Please help asap! Will give brainliest and thanks! Thank you so much!

sveta [45]

Answer:

A. absolute value f(-5)=6

B. linear g(0.2)= 0.3

C. absolute value p(-3)=13

Step-by-step explanation:

f(-5)=|(-5)-3|-2

=|-8|-2

=8-2

=6

g(0.2)= 1.5(0.2)

=0.3

p(-3)=|7-2(-3)|

=|7+6|

=13

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3 years ago