Step-by-step explanation:
5x - 1 - 2 > -5 -5x + 3
➡ 5x -3 > -2 -5x
➡ 10x > 1
➡ x > 1/10
M= (x+n)/p
Mp= x + n
x= n - Mp
Answer:
1 and 11/20
Step-by-step explanation:
3/4 + 4/5
= 15/20 + 16/20
= 31/20
= 1 and 11/20
Hope this helped!
Answer: (55,9) Explanation is below.
Step-by-step explanation:
What you want to do is try to mutliply one of your equations so that either y or x will be canceled out.
Here is the example:
Say you want to get rid of x, you can multiply the first equation: x-5y=10 by -2 to match the second equation: -2x+6y=-16.
Therefore, the first equation would become -2(x-5y=10)=> -2x+10y=-20
Then subtract the first equation from the second:
(-2x+6y= -16)
- (-2x+10y = -20)
-------------------------
=> 0x-4y= -36
Simplify and then you get y=9.
To find x, plug in y into one of the equations: x-5(9)=10 => x-45=10 => x=55
Sorry if I didn't explain it correctly.
Have a nice day! :D
This question presents an interesting pattern.
The rule/pattern to be followed here is:
Left side of the number looking at the previous one: (First digit x Third digit + 1)
Right side: (Second digit x Fourth digit -1)
For example, let us take 6447. Let us look at it's previous number, 9876.
Now,
and
![8\times 6-1=47](https://tex.z-dn.net/?f=%208%5Ctimes%206-1%3D47%20)
that is how we got 6447
Again, for the third number, 2527, let us look at it's previous number, 6447
Now, ![6\times 4+1=25](https://tex.z-dn.net/?f=%206%5Ctimes%204%2B1%3D25%20%20)
and ![4\times 7-1=27](https://tex.z-dn.net/?f=%204%5Ctimes%207-1%3D27%20)
that is how we got 2527
Going by the same logic, the missing number should be 534.
This we got by applying the rule of the pattern as:
![(2\times 2)+1=5](https://tex.z-dn.net/?f=%20%282%5Ctimes%202%29%2B1%3D5%20)
and
![(5\times 7)-1=34](https://tex.z-dn.net/?f=%20%285%5Ctimes%207%29-1%3D34%20)
Thus, we got 534.