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2 years ago

Solve the following system of equations by substitution. Show all steps.

Mathematics

1 answer:

Alinara [238K]2 years ago

4 0

Answer:

Given system of equations:

$\begin{cases}f(x)=-x^2+2x+3\\g(x)=-2x+3\end{cases}$

To solve by substitution, equate the equations and solve for x:

$\begin{aligned}f(x) & = g(x)\\\implies -x^2+2x+3 & = -2x+3\\-x^2+4x & = 0\\x^2-4x & = 0\\x(x-4) & = 0\\\implies x & = 0\\\implies x-4 & = 0 \implies x=4\end{aligned}$

Therefore, the x-values of the solution are $x = 0$ and $x = 4$ .

To find the y-values of the solution, substitute the found values of x into the functions:

$f(0)=-(0)^2+2(0)+3=3$

$g(0)=-2(0)+3=3$

$f(4)=-(4)^2+2(4)+3=-5$

$g(4)=-2(4)+3=-5$

Therefore, the solutions to the given system of equations are:

$(0, 3)$ and $(4, -5)$

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Find out if the 3 positions are on the same line or not (3,2,0) (1, -1,2) (5,5, 2)

sattari [20]

Answer:

The three positions are not on the same line.

Step-by-step explanation:

We have three points: A:(3,2,0), B:(1,-1,2) and C:(5,5,2).

Let's build a vector that goes from one point to another; that vector will be the director of a line (if we draw a vector that goes from A to B, that vector will be the direction of the line that pass by A and B because it does not change). In order to build that vector, let's subtract B from A:

$A-B=(3,2,0)-(1,-1,2)=(2,3,-2)$

The equation of a line is:

$p=p_0+rt$

Where p is every singular point of the line, $p_0$ is a particular point of the line (any that we are sure that it is on the line), r is the director vector and t is the independent variable.

Now we have the director vector: (2,3,-2), and we can verify that A and B are on the line:

$p=p_0+(2,3,-2)t$

Because there is a value for t that satisfies both A and B: If we do $p_0=(3,2,0)$ and t=0, we are going to obtain the point p=A; and if we do t=-1, we are going to obtain p=B. Let's see that:

$p=(3,2,0)+(2,3,-2)*0=(3,2,0)\\p=A\\p=(3,2,0)+(2,3,-2)*-1=(1,-1,2)\\p=B\\$

If C is also in the same line, C must accomplish the equation: $p=(3,2,0)+(2,3,-2)t$ , so:

$C=(5,5,2)=(3,2,0)+(2,3,-2)t$

Let's simplify the equation writing the parametric equation, which is just to write the equation for each dimension:

$5=3+2t\\5=2-3t\\2=-2t\\$

You can verify that there is not a value of t that satisfies all three equations, so, the point C is not on the same line as A and B; which means that A, B and C are not on the same line.

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2 years ago

Find a point on the ellipsoid x2+y2+4z2=36x2+y2+4z2=36 where the tangent plane is perpendicular to the line with parametric equa

Anvisha [2.4K]

Answer:

A point on the ellipsoid is (-4,2,2) or (4,-2,-2)

Step-by-step explanation:

Given equation of ellipsoid f(x,y,z) : $x^2+y^2+4z^2=36$