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max2010maxim [7]
11 months ago
10

Determine whether the series converges or diverges Please, check the image

Mathematics
1 answer:
bagirrra123 [75]11 months ago
5 0

The series as represented in the task content is divergent and hence; diverges.

<h3>What convergence and divergence in series?</h3>

It follows from the task content that the series defined by the summation expression as represented above is to be identified as divergent or convergent.

It is noteworthy to know that;

If a sequence converges, it means that the limit of the sequence exists as n → ∞. Also, if the limit of the sequence as n → ∞ does not exist, Then, such series is said to diverges.

Therefore, by evaluation as the limit of the expression k sin²k / 1 + k³ as k → ∞ is; Undefined and hence does not exist.

Read more on convergence and divergence of series;

brainly.com/question/28169281

#SPJ1

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then she turns around and grabs those 4329.73 and put them in an account getting 8% APR I assume, so is annual compounding, for 7 years.

\bf \qquad \textit{Compound Interest Earned Amount}&#10;\\\\&#10;A=P\left(1+\frac{r}{n}\right)^{nt}&#10;\quad &#10;\begin{cases}&#10;A=\textit{accumulated amount}\\&#10;P=\textit{original amount deposited}\to &\$4329.73\\&#10;r=rate\to 8\%\to \frac{8}{100}\to &0.08\\&#10;n=&#10;\begin{array}{llll}&#10;\textit{times it compounds per year}\\&#10;\textit{annually, thus once}&#10;\end{array}\to &1\\&#10;t=years\to &7&#10;\end{cases}&#10;\\\\\\&#10;A=4329.73\left(1+\frac{0.08}{1}\right)^{1\cdot 7}\implies A=4329.73(1.08)^7\\\\\\ A\approx 7420.396

add both amounts, and that's her investment for the 11 years.
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