Answer:
Given that the events A and B are mutually exclusive.
P(A) = 0.1
P(B) = 0.4
Mutually Exclusive Events: When two events are Mutually Exclusive it is impossible for them to happen together i.e
If A and B are two events then; P(A and B) = 0
then;
P(A or B) = P(A) +P(B)
By the definition of mutually exclusive events;
P(A or B) = P(A) +P(B) ......[1]
Substitute the values of P(A) = 0.1 and P(B) = 0.4 in [1] we have;
P(A or B) = P(A) +P(B) = 0.1+0.4 = 0.5
Answer:
y=450+40x y=975-65x
Step-by-step explanation:
at five months they will have the same amount of money in their accounts
Step-by-step explanation:
1. we have to write the system specifications as:
A(x,y) give us the meaning that the consule x can be accessed when y is in a faulty condition
∀y∃A(x,y)
2. B(x,y) shows that users email has sent a message, y. Which is in the archive. C(x) shows the email address of user x is retrievable
∀x∃y[B(x,y)→c(x)]
3. D(x,y) shows that x can detect breach y'' and we have E(z) that tells us there is a compromise of z
∀y∃xD(x,y)↔ ∃zE(z)
4. F(x,y,z)
Y and z are distinct point ends which x connects
We have,
∀y∀z∃x∃a[x ≠a →F(x,y,z)^F(a,y,z)
5. G(x,y)
X knowst the password of y' and H(x) means that we have x to be a system administrator
∀x[H(x)→∀yG(x,y)] ∃x[H(x)^∀yG(x,y)]
That’s all? That give me no info to help you bud
Answer:
33 girls
Step-by-step explanation:
This is the answer because:
1) 3/4 of 44 is 33 because 1/2 of 44 is 11
a) 11 x 3 = 33
Hope this helps! :)
