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ollegr [7]
3 years ago
15

The events A and B are mutually exclusive. If ​P(A)=0.1 and ​P(B)=0.4​, what is​ P(A or​ B)? ASAP

Mathematics
1 answer:
Gemiola [76]3 years ago
6 0

Answer:

Given that the events A and B are mutually exclusive.

P(A) = 0.1

P(B) = 0.4

Mutually Exclusive Events: When two events are Mutually Exclusive it is impossible for them to happen together i.e

If A and B are two events then; P(A and B) = 0

then;

P(A or B) = P(A) +P(B)

By the definition of mutually exclusive events;

P(A or B) = P(A) +P(B)                     ......[1]

Substitute the values of P(A) = 0.1 and P(B) = 0.4 in [1] we have;

P(A or B) = P(A) +P(B) = 0.1+0.4 = 0.5




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2 years ago
This table shows the number of points two teams scored in five games
mezya [45]

Answer:

2.16

Step-by-step explanation:

The question is on mean absolute deviation

The general formula ,

Mean deviation = sum║x-μ║/N where  x is the each individual value, μ is the mean and N is number of values

<u>Team 1</u>

Finding the mean ;

mean= \frac{51+47+35+48+64}{5}  =49

Points     Absolute Deviation from mean

51                          2

47                         2

35                        14

48                         1

64                         15

<u>Sum    </u>                34          

Absolute mean deviation = 34/5= 6.8

<u>Team 2</u>

Finding the mean

mean=\frac{27+55+53+38+41}{5} = 42.8

Points                      Absolute deviation from the mean

27                                    15.8

55                                    12.2

53                                     10.2

38                                      4.8

41                                       1.8

<u>Sum                                 44.8        </u>

Absolute deviation from the mean = 44.8/5 =8.96

Solution

Difference in mean absolute deviation of the two teams = 8.96-6.8 = 2.16

5 0
3 years ago
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