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frozen [14]
3 years ago
15

Suppose you & your friends are going to the movies.The amount of money you spend for tickets varies directly with the number

of people buying tickets.If you spend $48 for six tickets ,What is the constant of variation?
Mathematics
1 answer:
mojhsa [17]3 years ago
3 0
This is the equation you need to use: y = kx
So, let's put it this way:
y can be the total amount of money you spend (so $48), and x the number of people (6)

y=kx
48=k*6
k = 48/6
k = 8

The constant variation, and the price of one ticket is 8. 
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stiv31 [10]

Hey there!!

We know angle DEC = angle AEB

Hence,

... 4x + 12 = 5x - 10

... - x = - 22

... x = 22

4 ( 22 ) + 12

88 + 12

100° is the answer.

Hope my answer helps!

7 0
3 years ago
Read the following statement. If a number is divisible by 2,then it is even what is the inverse of this statement?
Lapatulllka [165]

Answer:

If it is an even number, then it is divisible by 2

Step-by-step explanation:

You flip the order of statements.  One statement is "a number is divisible by 2", the other is "it is even" is the other.  

7 0
4 years ago
You and three friends are planning a trip. You want to keep the cost below $90 per person. Write and solve an inequality that re
velikii [3]

Answer:   x < 360

Step-by-step explanation:

Let x be the total cost for the trip.

And, Here the total number of person = 4

Therefore, the cost for each person = x/4

And,   According to the question, The cost must below $90 per person.

Therefore, x/4 < 90

⇒   x < 360

Which is the required inequality for the situation.


8 0
3 years ago
Ap calc multiple choice question; attached below<br> please explain how, please!
anygoal [31]

Answer:

C. \frac{f(b)-f(1)}{b-1}=20

General Formulas and Concepts:

<u>Calculus</u>

  • Mean Value Theorem (MVT) - If f is continuous on interval [a, b], then there is a c∈[a, b] such that  f'(c)=\frac{f(b)-f(a)}{b-a}
  • MVT is also Average Value

Step-by-step explanation:

<u>Step 1: Define</u>

f(x)=e^{2x}

f'(c) = 20

Interval [1, b]

<u>Step 2: Check/Identify</u>

Function [1, b] is continuous.

Derivative [1, b] is continuous.

∴ There exists a c∈[1, b] such that f'(c)=\frac{f(b)-f(a)}{b-a}

<u>Step 3: Mean Value Theorem</u>

  1. Substitute:                    20=\frac{ f(b)-f(1)}{b-1}
  2. Rewrite:                        \frac{ f(b)-f(1)}{b-1}=20

And we have our final answer!

5 0
3 years ago
What angle has a tangent and sine that are both negative? <br><br> 300<br> 210 <br> 45 <br> 150
zimovet [89]

Answer:

300^{\circ}

Step-by-step explanation:

\text{In quadrant IV, both ratios of tangent and sine  are negative.}\\ \\300^{\circ}~ \text{lies in the fourth quadrant, so}~ \tan 300^{\circ}  ~ \text{and}~ \sin 300^{\circ}~ \text{are negative.}

6 0
2 years ago
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