$\frac{1}{2}x+\frac{1}{4}y=6 \ \ \ |\times 2 \\
\frac{1}{5}x+\frac{1}{3}y=1 \ \ \ |\times (-5) \\ \\
x+\frac{1}{2}y=12 \\
\underline{-x-\frac{5}{3}y=-5} \\
\frac{1}{2}y-\frac{5}{3}y=12-5 \\
\frac{3}{6}y-\frac{10}{6}y=7 \\
-\frac{7}{6}y=7 \\
y=7 \times (-\frac{6}{7}) \\
y=-6 \\ \\
x+\frac{1}{2}y=12 \\
x+\frac{1}{2} \times (-6)=12 \\
x-3=12 \\
x=12+3 \\
x=15 \\ \\
\boxed{(x,y)=(15,-6)}$

3 0

3 years ago

Read 2 more answers

− ( x + 3 ) − 2 ( 4 x − 3 )<br> I need the correct steps

lianna [129]

Answer:

-9x + 3

Step-by-step explanation:

You would distribute first.

− ( x + 3 ) − 2 ( 4x − 3 ) → -x − 3 − 8x + 6

(If you see a negative sign in front of a parenthesis without a number, its usually a negative 1)

From there, you would combine like terms.

-x − 3 − 8x + 6 → -9x + 3

8 0

3 years ago

Quaderlital PQRS is a scaled copy of quaderalital ABCD. Point P corresponds to A, Q to B , R to C and S to D if the distance fro

jekas [21]

Answer:

This question is incomplete.. is there an image?

Step-by-step explanation:

8 0

3 years ago