All categories

3 years ago

Is the following sequence arithmetic? If so, identify the common difference. 2.9, 2.7, 2.5, 2.3,

Mathematics

2 answers:

Alenkasestr [34]3 years ago

3 0

The common difference is -2

Goshia [24]3 years ago

3 0

Notice that 2.7 = 2.9 - 0.2; 2.5 = 2.7 - 0.2, and so on. So the common difference is -0.2.

You might be interested in

If the sine of an acute angle is 3/5, what is the cosine of that angle?

Korvikt [17]

Answer:

The cosine of the angle is 4/5.

Step-by-step explanation:

An acute angle is between 0º and 90º, in the first quadrant of the trigonometric circle, in which both the sine and the cosine are positive values.

For each angle $\alpha$ , we have that:

$\sin^{2}{\alpha} + \cos^{2}{\alpha} = 1$

We have that:

$\sin{\alpha} = \frac{3}{5}$

$\sin^{2}{\alpha} + \cos^{2}{\alpha} = 1$

$(\frac{3}{5})^{2} + \cos^{2}{\alpha} = 1$

$\cos^{2}{\alpha} = \frac{16}{25}$

$\cos{\alpha} = \frac{4}{5}$

The cosine of the angle is 4/5.

8 0

2 years ago

The formula for the area A of a rectangle with length l and width w is A = l ⋅ w . Find A if: l = 23 feet and w = 15 feet The ar

dexar [7]

Answer:

345 sq. ft

Step-by-step explanation:

You know that the area is the length times the width. Simply plug in values to your equation:

A = l * w

A = 23 * 15

A = 345

The area is 345 square feet.

3 0

3 years ago

Rearrange these equations in the form y=mc+c (see attached file)

BlackZzzverrR [31]

Step-by-step explanation:

Follow the Pic given above

7 0

2 years ago

Prove that :( 1 + 1/<img src="https://tex.z-dn.net/?f=tan%5E%7B2%7DA" id="TexFormula1" title="tan^{2}A" alt="tan^{2}A" align="ab

Aliun [14]

Answer:

See explanation

Step-by-step explanation:

Simplify left and right parts separately.

Left part:

$\left(1+\dfrac{1}{\tan^2A}\right)\left(1+\dfrac{1}{\cot ^2A}\right)\\ \\=\left(1+\dfrac{1}{\frac{\sin^2A}{\cos^2A}}\right)\left(1+\dfrac{1}{\frac{\cos^2A}{\sin^2A}}\right)\\ \\=\left(1+\dfrac{\cos^2A}{\sin^2A}\right)\left(1+\dfrac{\sin^2A}{\cos^2A}\right)\\ \\=\dfrac{\sin^2A+\cos^2A}{\sin^2A}\cdot \dfrac{\cos^2A+\sin^A}{\cos^2A}\\ \\=\dfrac{1}{\sin^2A}\cdot \dfrac{1}{\cos^2A}\\ \\=\dfrac{1}{\sin^2A\cos^2A}$