Answer:
Step-by-step explanation:
For each component, there are only two possible outcomes. Either it fails, or it does not. The components are independent. We want to know how many outcomes until r failures. The expected value is given by
In which r is the number of failures we want and p is the probability of a failure.
In this problem, we have that:
r = 1 because we want the first failed unit.
![p = 0.4[\tex]So[tex]E = \frac{r}{p} = \frac{1}{0.4} = 2.5](https://tex.z-dn.net/?f=p%20%3D%200.4%5B%5Ctex%5D%3C%2Fp%3E%3Cp%3ESo%3C%2Fp%3E%3Cp%3E%5Btex%5DE%20%3D%20%5Cfrac%7Br%7D%7Bp%7D%20%3D%20%5Cfrac%7B1%7D%7B0.4%7D%20%3D%202.5)
The expected number of systems inspected until the first failed unit is 2.5
Hello!
Answer:⇒⇒⇒⇒⇒=
Explanation:
↓↓↓↓↓↓↓↓↓↓↓↓
Group like terms:
↓↓↓↓↓↓↓↓↓↓↓↓↓↓
Add similar elements.
Hope this helps!
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-Charlie
Answer:
Step-by-step explanation:
If (x+8) is a factor of f(x), then for some expression p, we have ...
f(x) = (x+8)p
Evaluated at x=-8, this gives ...
f(-8) = (-8+8)p = 0p
f(-8) = 0 . . . . must be true
_____
Similarly, f(8) = (8+8)p = 16p. This may or may not be zero, depending on the factors of p. The only offered statement that <em>must</em> be true is the one shown above.
Answer:
iwillanswer
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17 one point shots and 39 two point shots were made
Solution:
Given that,
At a basketball game, a team made 56 successful shots
They were a combination of 1- and 2-point shots
Let "x" be the number of 1 point shots
Then, 56 - x is the number of two point shots
The team scored 95 points in all
Therefore,
1(number of 1 point shots) + 2(number of two point shots) = 95
x + 2(56 - x) = 95
x + 112 - 2x = 95
x = 112 - 95
x = 17
Then, number of two point shots = 56 - x = 56 - 17 = 39
Thus 17 one point shots and 39 two point shots were made
Answer:
D
Step-by-step explanation:
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