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san4es73 [151]
2 years ago
8

If sin A + sin^3 A = cos^2 A, prove that cos^6 A - 4cos^4 A + 8cos^2 A = 4.

Mathematics
2 answers:
ZanzabumX [31]2 years ago
6 0

Answer:

Step-by-step explanation:

sinA+sin

3

A=cos

2

A

⇒sinA[1+sin

2

A]=cos

2

A

⇒sinA[1+1−cos

2

A]=cos

2

A

squaring on both sides.

⇒sin

2

A[4+cos

4

A−4cos

2

A]=cos

4

A

⇒(1−cos

2

A)[4+cos

4

A−9cos

2

A]=cos

4

A

⇒4+cos

4

A−4cos

2

A−64cot

2

A−cos

6

A+9cos

4

A=cos

4

A

⇒

cos

6

A−4cos

4

A+8cos

2

A=4

​

Hence Prove

Sphinxa [80]2 years ago
4 0

Answer:

Step-by-step explanation:

sinA(1+sin^2A) = cos^2A

sinA(2 -cos^2A) = cos^2A

Squaring both sides,

sin^2A(4-4cos^2A +cos^4A) = cos^4A

(1-cos^2A)(4-4cos^2A +cos^4A) = cos^4A

4-4cos^2A +cos^4A-4cos^2A+4cos^4A-cos^6A = cos^4A

4 -cos^6A +4cos^4A -8cos^2A = 0

cos^6A - 4 cos^4A + 8cos^2A = 4

hence proveproven

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<h3>What is a linear function?</h3>

A linear function is modeled by:

y = mx + b

In which:

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In this problem:

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I need helpppp (10 points )
irga5000 [103]

Answer:  The flagpole is about 22.3 feet tall.

This is roughly the size of a two story building, assuming each floor is 10 feet or so.

Since this height is under 25 ft, this flagpole is in compliance with the regulation.

=====================================================

Work Shown:

The horizontal leg of the triangle is 36 ft. This is the adjacent leg to the reference angle 25 degrees.

The vertical leg of the triangle is x-5.5, and this leg is the opposite side to the reference angle 25 degrees.

Use the tangent rule to connect the opposite and adjacent sides.

Solve for x.

tan(angle) = opposite/adjacent

tan(25) = (x-5.5)/36

36*tan(25) = x-5.5

x-5.5 = 36*tan(25)

x = 36*tan(25)+5.5

x = 22.28707569358

x = 22.3 ft is the approximate height of the flagpole

Make sure your calculator is in degree mode.

The height is not over 25 ft, so this flagpole meets the requirements.

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