If you use FOIL to multiply these two brackets, it will lead you what is exactly written (xa+xb+ya+yb)
so it is correct
A
Step-by-step explanation:
(Assuming that this triangle is isosceles)
If this triangle is isosceles, then x° is going to be equal to its twin angle; 40°.
We can solve for z now.
180 = 40 + 40 + z
180 = 80 + z
Subtract 80 from both sides.
100 = z
z = 100°
Now that we know z = 100 degrees, we can begin to solve the expression (3x -20)
The expression sits on a 180° line and the angle z (100°) shares the line with the expression (3x - 20)°
180 = 100 + (3x - 20)
Subtract 100 from both sides.
80 = 3x - 20
Add 20 to both sides to isolate 3x
100 = 3x
Divide by 3 on both sides.
100/3 = 3x/3
33.33... = x
Answer:
1200 students at the school
Step-by-step explanation:
Let x be the total number of students at the school
50% ride the bus
600 students ride the bus
x*50% = 600
Changing to decimal form
.50x = 600
Divide each side by .5
.50x/.5 = 600/.5
x =1200
1200 students at the school
The absolute and relative cost difference in the restaurant and copycat meal are :
- Copycat meal is $4.20 less than restaurant meal
- Restaurant meal cost 1.88 times as much as copycat meal
- Copycat meal is 53% of the cost of restaurant meal
Cost of restaurant meal = $8.95
Cost of copycat version = $4.75
1.)
Difference in cost of meal for both version :
Cost of restaurant meal - Cost of copycat version
($8.95 - $4.75) = $4.20.
The copycat meal is $4.20 less than the restaurant meal
2.)
Cost of restaurant meal ÷ Cost of copycat version
($8.95 ÷ $4.75) = 1.884 = 1.88(2 decimal places)
The restaurant meal cost 1.88 times as much as the copycat meal
3.)
Percentage = (8.95 - 4.75) × 100% = 53.07% = 53%(nearest whole number)
The copycat meal is 53% of the cost of restaurant meal
Therefore, the relative and absolute cost difference are $4.20, 1.88 times and 53%
Learn more :brainly.com/question/13218948
Answer:
Step-by-step explanation:
<u>Linear Combination Of Vectors
</u>
One vector 
is a linear combination of 
and 
if there are two scalars 
such as
In our case, all the vectors are given in 
but there are only two possible components for the linear combination. This indicates that only two conditions can be used to determine both scalars, and the other condition must be satisfied once the scalars are found.
We have
We set the equation
Multiplying both scalars by the vectors
Equating each coordinate, we get
Adding the first and the third equations:
Replacing in the first equation
We must test if those values make the second equation become an identity
The second equation complies with the values of 
and 
, so the solution is
