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3 years ago

17-5(2×-9)=-(-6×+10)+4 Please help me with this problem

Mathematics

1 answer:

uranmaximum [27]3 years ago

4 0

Answer:

x = 17/4 = 4.25

Step-by-step explanation:

We assume your multiplication symbol (×) is intended to be a variable (x).

Simplifying, we have ...

17 -10x +45 = 6x -10 +4

68 = 16x

68/16 = x = 17/4 = 4.25

Check

17 -5(2(4.25) -9) = -(-6(4.25) +10) +4

17 -5(8.50 -9) = -(-25.5 +10) +4

17 -5(-0.5) = 15.5 +4

17 +2.5 = 19.5 . . . . . . true

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Which expression is equivalent to (2^1/2 x 2^3/4)^2

Lorico [155]

We basically use rules of indices or exponents on this one and simplify.

$({2^{1/2}*2^{3/4})^{2}$

When we have same base to a power multiplied together, we add the exponents. So we have,

$(2^{1/2+3/4})^{2}\\(2^{5/4})^{2} \\$

When we have power raised to a power, we multiply the powers. So we have,

$2^{10/4}$

Simplifying the fraction, we have

$2^{5/2}$ . Since the answer choices have a square root sign, this can be changed to include square roots and powers using the formula,

$\sqrt[n]{x^{m}} = x^{m/n}$ .

Now we can write $2^{5/2}$ as $\sqrt[2]{2^{5}}$ .

Just omit the 2 outside the square root sign as we don't need to write that due to convention. So we have $\sqrt{2^{5}}$ . This is answer choice (B).

ANSWER: B

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3 years ago

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Which equation could be solved using this application of the quadratic formula?

Alex_Xolod [135]

Answer:

C. x^2 + 2x - 1 = 3

Step-by-step explanation:

The standard form of a quadratic equation is

ax^2 + bx + c = 0

We need to use the quadratic formula and the given expression to find the values of a, b, and c.

The quadratic formula is

$x = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

Where the formula has -b, the problem has -2, so b = 2.

Now we have

ax^2 + 2x + c = 0

In the denominator, where the formula has 2a, the problem has 2(1), so a = 1.

Now we have

x^2 + 2x + c = 0

Inside the root, the quadratic formula has -4ac. the problem shows -4(1)(-4). Since we already know that a = 1, then c = -4.

Now we have

x^2 + 2x - 4 = 0

Let's look at choice A.

x^2 + 1 = 2x - 3

Subtract 2x from both sides. Add 3 to both sides.

x^2 - 2x + 4 = 0 This is not it!

Let's look at choice B.

x^2 - 2x - 1 = 3

Subtract 3 from both sides.

x^2 - 2x - 4 = 0 This is not it!

Let's look at choice C.

x^2 + 2x - 1 = 3

Subtract 3 from both sides.

x^2 + 2x - 4 = 0 This is it!

Answer: C. x^2 + 2x - 1 = 3

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3 years ago

In the Pythagorean theorem c represents Which side

Anvisha [2.4K]

Answer:

Hypotenuse

Step-by-step explanation:

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3 years ago

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What does the y-axis show? and What does the x-axis show?

vivado [14]

Answer:

x-axis shows the years and the y-axis shows the amount of tickets that are sold.

Step-by-step explanation:

The x-axis shows the years that pass. The y-axis shows how many tickets are sold each year. As each year passes, the amount of tickets sold increases, decreases, or stays the same.

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3 years ago

The equations of two lines are given below.

9966 [12]

The lines are neither parallel nor perpendicular

<h3>How to determine the relationship between the lines?</h3>

The equations of the lines are given as

3 x minus y equals 5

3 y equals x minus 15

Rewrite the equations properly

3x - y = 5

3y = x - 15

Make y the subject in both equations

In 3x - y = 5, we have

y = 3x + 5

In 3y = x - 15, we have

y = 1/3x - 5

The slopes of the two lines are

m1 = 3

m2 = 1/3

The above values are not equal, and they are not opposite reciprocal

This means that the lines are neither parallel nor perpendicular

Read more about linear equations at:

brainly.com/question/14323743

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2 years ago