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miss Akunina [59]
3 years ago
12

Please show steps!!!

Mathematics
1 answer:
just olya [345]3 years ago
4 0

Answer:

  there is no price for which weekly revenue would be 1800

Step-by-step explanation:

If there is a solution to the equation ...

  r = 1800 = -4p² +40p +1287

then there is a solution to ...

  4p² -40p +513 = 0

Comparing this to the standard form quadratic equation

  ax^2+bx+c=0

we can match coefficients to see that ...

  • a = 4
  • b = -40
  • c = 513

The discriminant of a quadratic is ...

  d=b^2-4ac\\\\d=(-40)^2-4(4)(513) = 1600-8208 = -6608

When we fill in the numbers and evaluate, we find the discriminant is negative. This tells us that solutions to the equation are complex—there are no real solutions, meaning there is no price that will give $1800 weekly revenue.

_____

A graph shows the highest weekly revenue obtainable at any price is $1387, so there is no price that will give revenue of $1800.

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What is 27+3÷ 3 +4-1+72.4-34.24+6-4+75÷5 <br> Answer this fast please!
Dimas [21]

Answer:

86.16

Step-by-step explanation:

27+3÷ 3 +4-1+72.4-34.24+6-4+75÷5

PEMDAS

Multiply and divide first

3/3 is 1   and 75/5 = 15

Replace these into the equation

27+1 +4-1+72.4-34.24+6-4+15

Then add and subtract from left to right

31 +72.4-34.24+6-4+15

69.16+6-4+15

86.16

7 0
3 years ago
Read 2 more answers
Principal = $47,300 Rate = 3% Time = 4 months What will the total payment plus interest be?
motikmotik

Answer:

Simple Interest (I) =  Principle * Rate * Time

 

so I = PRT

 

P = $47300

R = 3% = 0.03

T = 4months = 0.33years

 

so

Assuming its per year after 4month

 

I = (47300)(0.03)(0.333333)

 

I = 472.999527

 

I = $473

 

Now we'd add the interest(I) to the Principle

 

$47300 + $473 = $47773.00

 

 

Assuming it is per month, after 4months

 

I = PRT

 

I = (47300)(0.03)(4)

 

I = $5676.00

 

Now add the interest to the principle

 

$47300 + $5676 = $52976.00

Step-by-step explanation:

there you go hope this help

3 0
3 years ago
A business school has a goal that the average number of years of work experience of its MBA applicants is more than three years.
gizmo_the_mogwai [7]

Answer:

z=\frac{3.1-3}{\frac{2.449}{\sqrt{47}}}=0.280    

p_v =P(z>0.280)=0.390  

If we compare the p value and the significance level assumed \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can't conclude that the height of men actually its NOT significant higher than 0.3 at 1% of signficance.  

Step-by-step explanation:

Data given and notation  

\bar X=3.1 represent the sample mean

\sigma=\sqrt{6} represent the sample standard deviation for the sample

n=47 sample size  

\mu_o =3 represent the value that we want to test

\alpha represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is higher than 3, the system of hypothesis would be:  

Null hypothesis:\mu \leq 3  

Alternative hypothesis:\mu > 3  

If we analyze the size for the sample is > 30 and we know the population deviation so is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}  (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

z=\frac{3.1-3}{\frac{2.449}{\sqrt{47}}}=0.280    

P-value

Since is a one side test the p value would be:  

p_v =P(z>0.280)=0.390  

Conclusion  

If we compare the p value and the significance level assumed \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can't conclude that the height of men actually its NOT significant higher than 0.3 at 1% of signficance.  

3 0
3 years ago
Find the average rate of change of the function f(x), represented by the graph, over the interval [0, 3]. Calculate the average
Over [174]

Answer:

[f(3) - f(0)]/(3-0)

[f(3) - f(0)]/3

7 0
3 years ago
Strawberries are $3.99 per pound. If a customer bought $30 worth, how many pounds did he buy? $
lubasha [3.4K]

Answer:

7.5

Step-by-step explanation:

Divide 30 by 3.99

  • 30/3.99=7.5
3 0
3 years ago
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