<span>
(1/6)/ 1.5 =
(1/6)/(15/10)=
1/6*10/15=10/90=1/9 width</span>
Answer:
m∠N = 32°
NQ = 106°
When finding inscribed angles like ∠N with the intercepted arc, the equation is ∠N=1/2MP. (Inscribed angles are always half the degree of the arc length.) Plug in the corresponding value to get ∠N=1/2(64) to get 32°. When finding the angle of the intercepted arc with inscribed angles like NQ, the equation is NQ=2(∠P). Plug in the corresponding value to get 2(53) to get 106°.
The quadratic equation that would model this scenario is

Let us take the side of the square = x
Area of the square = x²
Length of the rectangular garden = 2x
Width of the rectangular garden = x-16
So, the area of the new vegetable garden = length*width
Area of the new or rectangular vegetable garden = 2x(x-16)
<h3>What is a quadratic equation?</h3>
The polynomial equation whose highest degree is two is called a quadratic equation. The equation is given by
coefficient
non-zero.
Since it is given that
Area of square garden = area of the rectangular garden

Thus, the quadratic equation that would model this scenario is

To get more about quadratic equations refer to:
brainly.com/question/1214333