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tensa zangetsu [6.8K]
3 years ago
10

Find the average rate of change of the function f(x), represented by the graph, over the interval [0, 3]. Calculate the average

rate of change of f(x) over the interval [0, 3] using the formula . The value of f(3) is . The value of f(0) is . The average rate of change of f(x) over the interval [0,3] is .
Mathematics
1 answer:
Over [174]3 years ago
7 0

Answer:

[f(3) - f(0)]/(3-0)

[f(3) - f(0)]/3

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C (The lower left one)

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I saw that the vertex was equal to (-1,1) and that is the only answer that makes sense

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joanne buys a rectangular rug with an area of 35/4 square meters. The length of the rug is 7/2 meters. What is thw width, in met
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Find the measure of the three missing angles in the parallelogram below.
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The computer that controls a bank's automatic teller machine crashes a mean of 0.6 times per day. What is the probability that,
professor190 [17]

Answer:

0.2103 = 21.03% probability that, in any seven-day week, the computer will crash less than 3 times.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given interval.

Mean of 0.6 times a day

7 day week, so \mu = 7*0.6 = 4.2

What is the probability that, in any seven-day week, the computer will crash less than 3 times? Round your answer to four decimal places.

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)

In which

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-4.2}*(4.2)^{0}}{(0)!} = 0.0150

P(X = 1) = \frac{e^{-4.2}*(4.2)^{1}}{(1)!} = 0.0630

P(X = 2) = \frac{e^{-4.2}*(4.2)^{2}}{(2)!} = 0.1323

So

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0150 + 0.0630 + 0.1323 = 0.2103

0.2103 = 21.03% probability that, in any seven-day week, the computer will crash less than 3 times.

3 0
3 years ago
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