A spherical chocolate candy is being manufactured that has nougat center. The entire candy has a diameter of 9cm and the nougat
center has a diameter of 4cm. What is the volume of the chocolate portion of the candy
1 answer:
That would be the volume of the total shape minus the volume of the center.
V=(4πR^3)/3-(4πr^3)/3
V=(4π/3)(R^3-r^3), since R=9/2=4.5 and r=4/2=2 we have:
V=(4π/3)(4.5^3-2^3)
V=(4π/3)(91.125-8)
V=(4π/3)(83.125)
V=332.5π/3 cm^3
V≈348.19 cm^3 (to nearest hundredth of a ml or cubic centimeter)
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