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Evgesh-ka [11]
2 years ago
8

Jeanne needed to buy 258 yards of fabric, if the ribbon costs 10¢ per foot, what is the total cost of the ribbon in dollars?

Mathematics
1 answer:
ss7ja [257]2 years ago
7 0

Answer:

Step-by-step explanation:

1 yard is equal to 3 foot

10¢= 1 foot

30¢= 1 yard

30¢ x 258 yards= $77.40

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the calorie cafe is known for their hotdogs and burgers. the number of calories in a burger is 220 more than the number of calor
meriva

Answer:

  • Number of calories in burger = 620 calories
  • Number of calories in hotdog = 400 calories

Step-by-step explanation:

Number of calories in burger = x

Number of calories in hotdog = y

y = x - 220

x + 2y = 1,420

Substitution:

x + 2 * (x - 220) = 1,420

x + 2x - 440 = 1,420

3x = 1,420 + 440

x = 1,860 / 3

x = 620 calories

y = x - 220

= 620 - 220

= 400 calories

6 0
2 years ago
......i need help please..........​
makkiz [27]

Answer:

Step-by-step explanation:

So, TML = 104, right?

Now, we know that TMV + LMV is 104.

We also know that TMV is 60.

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LMV is simply 104 - 60 = 54

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5 0
3 years ago
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If m<9=97 and m<12=114, find each measure.
seropon [69]

Answer:

a. 97

b. 83

c.66

d. 114

e.83

f. 97

g. 114

h.66

i. 83

j. 66

k.83

l.97

m. 114

n. 66

6 0
3 years ago
Write 25/20 as a percentage
kolezko [41]
125% my guys im sorry if its wrong :(
5 0
2 years ago
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About Exercise 2.3.1: Proving conditional statements by contrapositive Prove each statement by contrapositive
Sladkaya [172]

Answer:

See proofs below

Step-by-step explanation:

A proof by counterpositive consists on assuming the negation of the conclusion and proving the negation of the hypothesis.

a) Assume that n is not odd. Then n is even, that is, n=2k for some integer k. Hence n²=4k²=2(2k²)=2t for some integer t=2k². Then n² is even, therefore n² is not odd. We have proved the counterpositive of this statement.

b) Assume that n is not even, then n is odd. Thus, n=2k+1 for some integer k. Now, n³=(2k+1)³=8k³+6k²+6k+1=2(4k³+3k²+3k)+1=2t+1 for the integer t=4k³+3k²+3k. Thus n³ is odd, that is, n³ is not even.

c) Suppose that n is not odd, that is, n is even. Now, n=2k for some integer k. Then 5n+3=10k+3=2(5k+1)+1, thus 5n+3 is odd, then 5n+3 is not even.

d) Suppose that n is not odd, then n is even. Now, n=2k for some integer k. Then n²-2n+7=4k²-4k+7=2(2k²-2k+3)+1. Hence n²-2n+7 is odd, that is, n²-2n+7 is not even.

e) Assume that -r is not irrational, then -r is rational. Since -1 is rational, then (-1)(-r)=r is rational. Thus r is not irrational.

f) Assume that 1/z is not irrational. Then 1/z is rational. Multiplucative inverses of rational numbers are rational, hence z is rational, that is, z is not irrational.

g) Suppose that z>y. We will prove that z³+zy²≤z²y+y³ is false, that is, we will prove that z³+zy²>z²y+y³. Multiply by the nonnegative number z² in the inequality z>y to get z³>z²y (here we assume z and y nonzero, in this case either z³>0=y³ is true or z³=0>y³ is true). On the other hand, multiply by z² (positive number) to get zy²>y³. Add both inequalities to obtain z³+zy²>z²y+y³ as required.

h) Suppose than n is even. Then n=2k, and n²=4k² is divisible by 4.

i) Assume that "z is irrational or y is irrational" is false. Then z is rational and y is rational. Rational numbers are closed under sum, then z+y is rational, that is, z+y is not irrational.

3 0
2 years ago
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