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3 years ago

DESPERATELY NEED HELP ON THIS PLEASE! X(

Mathematics

2 answers:

Reika [66]3 years ago

5 0

Answer:

27.19 Minutes

Step-by-step explanation:

So the Circumference is C = 2 $\pi$ r

C = 2· $\pi$ ·67.5 (the radius)

C ≈ 424.12 metres (rounded to nearest hundredth)

Then you take 424.12 metres and divide it by 0.26 metres (because it is 0.26 metres per seconds) (I like to make this weird table, I don't know how to describe it, you could do it like: $\frac{424.12 metres (times) 1 second}{0.26 metres}$ (I learned this table from chem, so let me know if you know what kind of table I'm talking about... Its a conversion table...)

The metres cancel out and you end with seconds

You end up getting 1631.23 (rounded to nearest hundredth) seconds. Divide that by 60 (seconds) and you'll get 27.19 (rounded to nearest hundredth) minutes

katen-ka-za [31]3 years ago

3 0

35.1 is the answer to this question

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PLZ help of u know the Answer for Sure.

anzhelika [568]

Answer:

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Step-by-step explanation:

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3 years ago

3 a. It takes Adriana 20 minutes to walk 5 blocks to the library. Complete the table of equivalent ratios to show Adriana’s two

Dafna11 [192]

Answer:

It takes 4 minutes per block and she can walk 12.5 blocks in 45 minutes.

Step-by-step explanation:

20 / 5 = 4 minutes per block

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5 + 5 + 2.5 = 12.5

Hope this helps, I did the test last year.

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2 years ago

10. The expression 4 (2x-5)+7(x+2) can be written in simplest form as

ankoles [38]

Answer:

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2 years ago

In basketball, hang time is the time that both of your feet are off the ground during a jump. The equation for hang time is t =

const2013 [10]

Considering the hang time equation, it is found that Player 1 jumped 0.68 feet higher than Player 2.

<h3>What is the hang time equation?</h3>

The hang-time of the ball for a player of jump h is given by:

$t = 2\left(\frac{2h}{32}\right)^{\frac{1}{2}}$

The expression can be simplified as:

$t = 2\sqrt{\frac{h}{16}}$

For a player that has a hang time of 0.9s, the jump is found as follows:

$0.9 = 2\sqrt{\frac{h}{16}}$

$\sqrt{\frac{h}{16}} = \frac{0.9}{2}$

$(\sqrt{\frac{h}{16}})^2 = \left(\frac{0.9}{2}\right)^2$

$h = 16\left(\frac{0.9}{2}\right)^2$

h = 3.24 feet.

For a player that has a hang time of 0.8s, the jump is found as follows:

$0.8 = 2\sqrt{\frac{h}{16}}$

$\sqrt{\frac{h}{16}} = \frac{0.8}{2}$

$(\sqrt{\frac{h}{16}})^2 = \left(\frac{0.8}{2}\right)^2$

$h = 16\left(\frac{0.8}{2}\right)^2$

h = 2.56 feet.

The difference is given by:

3.24 - 2.56 = 0.68 feet.

More can be learned about equations at brainly.com/question/25537936

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2 years ago

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2 years ago