10C6 = 10!/(6!*(10-6)!) = 10*9*8*7/(4*3*2*1) = 210
There are 210 ways to choose 6 from a group of 10.
Answer:
2 yards
Step-by-step explanation:
Answer:
use calculator and then solve it╮(─▽─)╭
Answer:
a= 200
b = 210
Step-by-step explanation:
My assumption is, we have to find the length of sides of rectangle
Given
perimeter = 2a + 2b = 820 ft (i) (here a is smaller side and b is larger side)
area = a*b = 42,000 ft^2 (ii)
from eq (1)
2a + 2b = 820
=> 2(a+b) = 820
=> a+b = 820/2
=> a + b = 410
=> a = 410-b (iii)
putting the value of a in eq(ii), we get
(410-b) *b = 42,000
410b - b^2 = 42,000
0 = b^2 - 410b + 42000
b^2 - 410b + 42000 = 0
b^2- 200b- 210b + 42000 = 0
b(b-200)-210(b-200) = 0
(b-200)(b-210) = 0
or
b= 210 and b = 200
if b is larger side than b =210
By putting value of b in eq(iii),
a = 410 -210 = 200
Answer:
-7
Step-by-step explanation:
h(x)={x-3}+1 if h(-5)
When h(-5) = {-5-3}+1 ={-8}+1= -8+1=-7
