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2 years ago

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Mathematics

1 answer:

yuradex [85]2 years ago

7 0

Greetings!

We can substitute the variables, so we only have to solve for one, per eqaution
$x=4y$
Therefore...
$3x-2y=20$
Is also equal to..
$3(4y)-2y=20$

Solve for y.
Combine Like terms.
$12y-2y=20$
$10y=20$
Divide both sides by 10.
$(10y)/10=(20)/10$
Simplify.
$y=2$

Now we can use the value of y to solve the other equation.
$x=4y$
Is also equal to...
$x=4(2)$

Solve for <em>x</em>.
Combine like terms.
$x=8$

The answer would be 8,2

Hope this helps.
-Benjamin

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2 years ago

A number is selected randomly from the integer from 10to30 what is the probability of picking a multiple of 4or5

arlik [135]

Answer:

$\frac{3}{7}$

Step-by-step explanation:

Start by finding how many integers there are from 10-30...

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1 year ago

You randomly pick two numbers from 1 to 9 (including 1 and 9). A number that is chosen once could be chosen again. If at least o

Mnenie [13.5K]

Assume that you only include whole numbers (1,2,3,4,5,6,7,8,9) and not 3.5 and such
so if 1 is odd and less than 5 then it is
1 or 3, since 5 isn't included
then the other number, to be less than 5 when added,
must be
1+x<5
3+x<5
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3+x<5
subtract 3
x<2
set of answer is 1
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1,2,3
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total possible=9
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2 years ago

When the smaller of two consecutive integers is added to four times the larger, the result is 49. Find the integers.

ryzh [129]

$4(n+1)+n=49\\
4n+4+n=49\\
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n=9\\
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$

These numbers are 9 and 10.

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2 years ago