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3 years ago

$875 at 9.5% compunded twice a year. How much money will there be in 5years?

1 answer:

5 0

P = A(1+i)ⁿ, where:
A= initial value
I = interest in %
n= period of compound investment.
However, if the interest is paid twice a year, that means you have to divide the interest by 2 and the period becomes twice n
P = 875(1+9.5%/2)⁵ˣ²
P = 875(1+4.75%)¹⁰
P =875( 1.0475)¹⁰
P = $1,391.7

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The question is in the screenshot.

Musya8 [376]

Answer:

v = 4

Step-by-step explanation:

u + at = v

a (-2) multiplied by t (3) = -6

-6 + u (10) = 4

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3 years ago

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Evaluate x+y when x=13 and y=−74. Write your answer as a fractionin simplest form

Fofino [41]

The value of the expression is -35.

Step-by-step explanation:

Consider the provided expression.

3x + y 

We need to find the value of the expression for x=13 and y=−74 .

Substitute the value of x=13 and y=−74 in the above expression as shown:

3 (13) + (-74)

39 - 74 

-35

 the value of the expression is -35.

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3 years ago

The box which measures 70cm X 36cm X 12cm is to be covered by a canvas. How many meters of canvas of width 80cm would be require

grigory [225]

Answer:

142.2 meters.

Step-by-step explanation:

We have been given that a box measures 70 cm X 36 cm X 12 cm is to be covered by a canvas.

Let us find total surface area of box using surface area formula of cuboid.

$\text{Total surface area of cuboid}=2(lb+bh+hl)$ , where,

$l$ = Length of cuboid,

$b$ = Breadth of cuboid,

$w$ = Width of cuboid.

$\text{Total surface area of box}=2(70\cdot36+36\cdot 12+12\cdot 70)$

$\text{Total surface area of box}=2(2520+432+840)$

$\text{Total surface area of box}=2(3792)$

$\text{Total surface area of box}=7584$

Therefore, the total surface area of box will be 7584 square cm.

To find the length of canvas that will cover 150 boxes, we will divide total surface area of 150 such boxes by width of canvass as total surface area of canvas will also be the same.

$\text{Width of canvas* Length of canvass}=\text{Total surface area of 150 boxes}$

$80\text{ cm}\times\text{ Length of canvass}=150\times 7584\text{cm}^2$

$\text{ Length of canvass}=\frac{150\times 7584\text{ cm}^2}{80\text{ cm}}$

$\text{ Length of canvass}=\frac{1137600\text{ cm}^2}{80\text{ cm}}$

$\text{ Length of canvass}=14220\text{ cm}$

Let us convert the length of canvas into meters by dividing 14220 by 100 as 1 meter equals to 100 cm.

$\text{ Length of canvass}=\frac{14220\text{ cm}}{100\frac{cm}{m}}$

$\text{ Length of canvass}=\frac{14220\text{ cm}}{100}\times\frac{m}{cm}$

$\text{ Length of canvass}=142.20\text{ m}$

Therefore, 142.2 meters of canvas of width 80 cm required to cover 150 such boxes.

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3 years ago

A 25 foot ladder is leaning against a house. It makes a 75 degree angle with the ground. How far is the base of the ladder from

Oduvanchick [21]

Look at the picture.

$\cos 75^\circ =\frac{x}{25} \\
25 \cos 75^\circ = x \\
25 \times 0.2588 \approx x \\
x \approx 6.47$

The base of the ladder is 6.47 feet from the house.

4 0

3 years ago

A Ladder that is 32 ft long leans against a building. The angle of elevation of the ladder is 70 degrees. To the nearest tenth o

kolezko [41]

See the picture attached to better understand the problem

we know that
in the right triangle ABC
sin 70°=opposite side angle 70°/hypotenuse

in this problem
opposite side angle 70°=AB
hypotenuse=AC----> 32 ft
sin 70°=AB/32------> AB=32*sin 70°-----> AB=30.07 ----> AB=30.1 ft

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3 years ago

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