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ZanzabumX [31]
3 years ago
15

What ordered pair represents the y-intercept of the graph y = 2x - 3?

Mathematics
1 answer:
Rudik [331]3 years ago
3 0

Answer:

C. (0,-3)

Step-by-step explanation:

y = 2x - 3

We only need to focus on "- 3" because it represents "b" of the equation y = mx + b.

Since it is a y intercept, the coordinate must be at the y axis.

So,

x = 0

y = -3

(0,-3)

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Barry Beach was convicted of murder in 1983 and sentenced to life in prison without parole. In 2015, Governor Bullock commuted B
maria [59]

Answer:

The correct answer to the following question will be Option 1 (All Montana residents).

Step-by-step explanation:

  • Barry Beach told journalists managed to gather next to the front main entrance of Montana federal penitentiary across lunchtime that perhaps the point in time seemed to be 'surreal.'
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Other choices aren't linked to just the scenario in question. Option 1 seems to be the perfect solution.

8 0
3 years ago
How do you solve equations that contain addition or subtraction
ollegr [7]
To solve an addition problem, you simply add one number to the other. For example, If I want to add 4 to 5, I would write the equation 4 + 5 = 9. To solve a subtraction problem, you simply take a number away from another. For example, If I want to take 5 away from 9, I would write the equation 9 - 5 = 4. Hope I helped! :)
7 0
3 years ago
Find the equation of the line that contains the points P1(-4,8) and P2(-6,8)...
olga_2 [115]
The equation would just be x=8 since the x of both points is 8. 
6 0
3 years ago
PLEASE PLEASE HELP
stepan [7]

Answer:


38 divided by 16146.2 = 0.0023534949 then rounded to the nearest hundredth = 0.00

38. divided by 16146.2= The same as that one ^

1614.62 divided by 3.8= 424.9 then rounded you get 424.90

8 0
3 years ago
What is the approximate distance between the points (-3, -4) and (-8, 1) on a coordinate grid
tatyana61 [14]
\bf ~~~~~~~~~~~~\textit{distance between 2 points}
\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
%  (a,b)
&&(~ -3 &,& -4~) 
%  (c,d)
&&(~ -8 &,& 1~)
\end{array}\\\\\\ %  distance value
d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}
\\\\\\
d=\sqrt{[-8-(-3)]^2+[1-(-4)]^2}\implies d=\sqrt{(-8+3)^2+(1+4)^2}
\\\\\\
d=\sqrt{25+25}\implies d=\sqrt{2\cdot 25}\implies d=\sqrt{2\cdot 5^2}\implies d=5\sqrt{2}
4 0
3 years ago
Read 2 more answers
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