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2 years ago

Given that triangle LMN is similar to triangle GJH, what is the value of x?

Mathematics

1 answer:

inysia [295]2 years ago

4 0

Answer:

x = 53

Step-by-step explanation:

Similar means that the corresponding angles are congruent (the same) - basically what this means is that ∠L ≅ ∠G, ∠M ≅ ∠J, and ∠N ≅ ∠H.

Since we know that the angle measures in a triangle should add up to 180 and we know the measures of ∠L and ∠M already, we can do

180 = 67 + 60 + N

So, N = 180 - (67 + 60) = 180 - 127 = 53.

Since ∠N ≅ ∠H, ∠H = 53.

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3 years ago

This is really confusing. Thanks for helping.

Mandarinka [93]

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2 years ago

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2 years ago

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What value of x would make the figure a parallelogram (show your math please)

Verdich [7]

Answer:

Step-by-step explanation:

Diagonals of a parallelogram bisects each other.

Therefore,

4x = 8

x = 8/4

x = 2

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8 0

2 years ago

The solution to a quadric equation are x=2 and x=7. If k is a nonzero constant which of the following must be equal to the quadr

nikklg [1K]

Answer:

The quadratic equation form is x² - 9 x + 14 = 0

Step-by-step explanation:

Given in the question as ,

The solution of quadratic equation are x = 2 and x = 7

The constant K is a non-zero number

Now , let the quadratic equation be , ax² + bx + c = 0

And sum of roots = $\frac{ - b}{a}$

product of roots = $\frac{c}{a}$

So, 2 + 7 = $\frac{ - b}{a}$

Or, 2 × 7 = $\frac{c}{a}$

I.e $\frac{ - b}{a}$ = 9 , $\frac{c}{a}$ = 14

Or, b = - 9 a And c = 14 a

Put this value of b and c in standard form of quadratic equation

I.e ax² + bx + c = 0

Or, ax² - 9 ax + 14 a = 0

Or , a ( x² - 9 x + 14 ) = 0

∴ a = 0 And x² - 9 x + 14 = 0

Hence , The quadratic equation form is x² - 9 x + 14 = 0 Answer

7 0

2 years ago