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liubo4ka [24]
3 years ago
10

Twice a number increased by three times the number?

Mathematics
2 answers:
julia-pushkina [17]3 years ago
8 0

this is the answer

Step-by-step explanation:

2x+3

12345 [234]3 years ago
4 0

Answer:

2x+3x

Step-by-step explanation:

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In which year did the population grow the fastest ? Justify your answer using the average rate of change
ch4aika [34]
1957 avg rate of 500,000 per every person
3 0
3 years ago
My equation is wrong so can someone pls explain how to do it ?? thank you
RoseWind [281]

Answer: (a)350 + 0.05x ≥ 600 (b) $5000


Explanation:

Fixed Salary = $350

Variable = 5% on sales

Let x the sales amount


Equation: 350 + 0.05x ≥ 600


350 + 0.05x ≥ 600

0.05x ≥ 600 - 350

0.05x ≥ 250

x ≥ $5000

6 0
3 years ago
0.242 to the nearest hundredth
11Alexandr11 [23.1K]
Two digits after the decimal point it the hundredths place
so we want to round to the place 4 is in
The number after 4 is 2, so we will round down
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3 0
3 years ago
Consider a parent population with mean 75 and a standard deviation 7. The population doesn’t appear to have extreme skewness or
Aleks04 [339]

Answer:

a) \bar X \sim N(\mu=375, \sigma={\bar X}=\frac{7}{\sqrt{40}}=1.107)

b) Since the sample size is large enough n>30 and the original distribution for the random variable X  doesn’t appear to have extreme skewness or outliers, the distribution for the sample mean would be bell shaped and symmetrical.

c) P(\bar X \leq 77)=P(Z

d) See figure attached

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Let X the random variable of interest. We know from the problem that the distribution for the random variable X is given by:

E(X) = 75

sd(X) = 7

We take a sample of n=40 . That represent the sample size

Part a

From the central limit theorem we know that the distribution for the sample mean \bar X is also normal and is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

\bar X \sim N(\mu=375, \sigma={\bar X}=\frac{7}{\sqrt{40}}=1.107)

Part b

Since the sample size is large enough n>30 and the original distribution for the random variable X  doesn’t appear to have extreme skewness or outliers, the distribution for the sample mean would be bell shaped and symmetrical.

Part c

In order to answer this question we can use the z score in order to find the probabilities, the formula given by:

z=\frac{\bar X- \mu}{\frac{\sigma}{\sqrt{n}}}

And we want to find this probability:

P(\bar X \leq 77)=P(Z

We can us the following excel code: "=NORM.DIST(1.807,0,1,TRUE)"

Part d

See the figure attached.

8 0
3 years ago
Explain why it is correct to claim that A/B < B/A is true.
PolarNik [594]

Answer:

Think of it as a small number and a large number. If the large number is being divided by a small number, of course that would be larger than the small number being divided by the large number.

3 0
3 years ago
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