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3 years ago

10

Twice a number increased by three times the number?

2 answers:

julia-pushkina [17]3 years ago

8 0

this is the answer

Step-by-step explanation:

2x+3

12345 [234]3 years ago

4 0

Answer:

2x+3x

Step-by-step explanation:

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Which graph below shows the rule:output 4 times input

Kipish [7]

Answer:bh5j67k

Step-by-step explanation:

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3 years ago

help asap im in a quiz, please show some sort of proof. and please dont say,¨ the answer is in the photo, and then send me a lin

Setler [38]

The answer would be D i think because if the two angles are to equal 72, and one of the angles equals 42, 72-42= 30. to find x, you’d do 30/6 which equals 5. so x=5 and the angle measure would be 30

4 0

3 years ago

What is the length of BC , rounded to the nearest tenth?

Arte-miy333 [17]

Step $1$

In the right triangle ADB

<u>Find the length of the segment AB</u>

Applying the Pythagorean Theorem

$AB^{2} =AD^{2}+BD^{2}$

we have

$AD=5\ units\\BD=12\ units$

substitute the values

$AB^{2}=5^{2}+12^{2}$

$AB^{2}=169$

$AB=13\ units$

Step $2$

In the right triangle ADB

<u>Find the cosine of the angle BAD</u>

we know that

$cos(BAD)=\frac{adjacent\ side }{hypotenuse}=\frac{AD}{AB}=\frac{5}{13}$

Step $3$

In the right triangle ABC

<u>Find the length of the segment AC</u>

we know that

$cos(BAC)=cos (BAD)=\frac{5}{13}$

$cos(BAC)=\frac{adjacent\ side }{hypotenuse}=\frac{AB}{AC}$

$\frac{5}{13}=\frac{AB}{AC}$

$\frac{5}{13}=\frac{13}{AC}$

solve for AC

$AC=(13*13)/5=33.8\ units$

Step $4$

<u>Find the length of the segment DC</u>

we know that

$DC=AC-AD$

we have

$AC=33.8\ units$

$AD=5\ units$

substitute the values

$DC=33.8\ units-5\ units$

$DC=28.8\ units$

Step $5$

<u>Find the length of the segment BC</u>

In the right triangle BDC

Applying the Pythagorean Theorem

$BC^{2} =BD^{2}+DC^{2}$

we have

$BD=12\ units\\DC=28.8\ units$

substitute the values

$BC^{2}=12^{2}+28.8^{2}$

$BC^{2}=973.44$

$BC=31.2\ units$

therefore

<u>the answer is</u>

$BC=31.2\ units$

8 0

3 years ago

Read 2 more answers

When a jug is half- filled with marbles, it weighs 2.6 kg. The jug weighs 4 kg when it is full. Find the weight of the empty jug

baherus [9]

the difference between a full jug and a jug that is half full will give us the weight of the marbles only in a half full jug:
4 - 2.6 = 1.4 kg

In a half full jug that weighs 2.6 kg, the weight of the marbles is 1.4 kg
the weight of the jug = 2.6 - 1.4 = 1.2 kg

5 0

3 years ago

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Y varies directly with x,and y=7 when x=2. What is the value of y when x=5?

Travka [436]

Y=10 bc y-x=5 then 5+5= 10

3 0

3 years ago