Question

(05.01 MC)

Answer 1

Answer:

It is one-half the area of a rectangle with sides 2 units × 3 units.

Step-by-step explanation:

we have the coordinates of triangle ABC

A(4,5),B(5,2),C(3,2)

Plot the coordinates of triangle to better understand the problem

see the attached figure

step 1

Find the area of triangle ABC

The triangle ABC is an isosceles triangle `(AB=AC)

The area of triangle ABC is

$A=\frac{1}{2}(BC)(AM)$

we have

$BC=5-3=2\ units$ ---> difference of the x-coordinates

$AM=5-2=3\ units$ ---> difference of the y-coordinates

substitute

$A=\frac{1}{2}(2)(3)=3\ units^2$

step 2

Find one-half the area of a rectangle with sides 2 units × 3 units

$A=\frac{1}{2} (2)(3)=3\ units^2$

therefore

The area of triangle ABC is one-half the area of a rectangle with sides 2 units × 3 units