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Alla [95]
2 years ago
12

Contrast the bonds that are formed from diatomic chlorine and diatomic oxygen.

Chemistry
1 answer:
melomori [17]2 years ago
6 0
<h3><u>Answer</u>;</h3>

Chlorine forms one covalent bond and oxygen forms two covalent bonds

<h3><u>Explanation</u>;</h3>
  • Covalent bond is a type of bond the occur when non-metal  atoms share electrons. Covalent atom may occur between two atoms in a molecule.
  • Diatomic molecule is a molecule consisting of two atoms. Halogens such as chlorine exist as diatomic gases by forming covalent bonds.
  • <em><u>Single covalent bond occurs when two atoms held together by sharing a pair of electrons, for example in diatomic molecules such as chlorine.</u></em>
  • <em><u>Double covalent bond is a bond that involves two shared pairs of electrons for example in oxygen molecule.</u></em> Triple covalent bond on the other hand is a bond formed by sharing three pairs of electrons between atoms, like in the case of nitrogen molecule.
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Manganese decreases from 4+ to 2+ (reduced and oxidizing agent) and nitrogen increases from 2+ to 5+ (oxidized and reducing agent).

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Hello there!

In this case, according to the given redox reaction, we rewrite it as a convenient first step:

2NO + 3MnO_2 + 4H^+ \rightarrow 2NO_3^- + 3Mn^{2+} + 2H_2O

Next, we assign the oxidation numbers as follows:

2N^{2+}O^{2-} + 3Mn^{4+}O^{-2}_2 + 4H^+ \rightarrow 2(N^{5+}O^{2-}_3)^- + 3Mn^{2+} + 2H^+_2O^{2-}

Thus, we can see that both manganese and nitrogen undergo a change in their oxidation number, the former decreases from 4+ to 2+ (reduced and oxidizing agent) and the latter increases from 2+ to 5+ (oxidized and reducing agent).

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