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galina1969 [7]
4 years ago
7

Nylon 6,6 may be formed by means of a condensation polymerization reaction in which hexamethylene diamine [NH2-(CH2)6-NH2] and a

dipic acid react with one another with the formation of water as a byproduct. What masses of________(a) hexamethylene diamine and(b) adipic acid are necessary to yield 26 kg of completely linear nylon 6,6? This polymerization reaction occurs according to the following equation:

Chemistry
1 answer:
Burka [1]4 years ago
3 0

Answer:

Mass of hexamethylenediamine= 13,470.62 g

Mass of adipic acid =  16,940.13 g

Explanation:

Nylon -6,6 is synthesized by poly-condensation of hexamethylenediamine [NH₂-(CH₂)₆-NH₂] and adipic acid (C₆H₁₀O₄).

Both of these are taken in equal equivalents and reacted to form nylon 6,6 and by-product water is also formed.

Molecular mass of hexamethylenediamine [NH₂-(CH₂)₆-NH₂] =116.21 g/mol

Molecular mass of adipic acid (C₆H₁₀O₄) = 146.1412 g/mol

Molecular mass of Nylon 6,6 (C₁₂H₂₀N₂O₂) = 224.3 g/mol

Using unitary method :

Mass of hexamethylenediamine required for 26,000 g of Nylon 6,6 if 116.21 g/mol is required for 224.3 g/mol, is:

= \frac{26,000 *  116.21}{224.3}

= 13,470.62 g

Mass of adipic acid required for 26,000 g of Nylon 6,6 if 146.1412 g/mol is required for 224.3 g/mol, is:

= \frac{26,000 *  146.1412}{224.3}

= 16,940.13 g

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Answer:

The electrons of an atom that can participate in the formation of chemical bonds with other atoms.

4 0
3 years ago
When of a certain molecular compound X are dissolved in of benzene , the freezing point of the solution is measured to be . Calc
puteri [66]

The question is incomplete. Here is the complete question.

When 2.10 g of a certain molecular compound X are dissolved in 65.0 g of benzene (C₆H₆), the freezing point of the solution is measured to be 3.5°C. Calculate the molar mass of X. If you need any additional information on benzene, use only what you find in the ALEKS Data resource. Also, be sure your answer has a unit symbol, and is rounded to 2 significant digits.

Answer: MM = 47.30 g/mol.

Explanation: There is a relationship between <u>freezing</u> <u>point</u> <u>depression</u> and <u>molality</u>. With this last one, is possible to calculate <u>molar</u> <u>mass</u> or molar weight of a compound.

<u>Freezing</u> <u>Point</u> <u>Depression</u> occurs when a solute is added to a solvent: the freezing point of the solvent decreases when a non-volatile solute is incremented.

<u>Molality</u> or <u>molal</u> <u>concentration</u> is a quantity of solute dissolved in a certain mass, in kg, of solvent. Its symbol is m and it's defined as

m=\frac{moles(solute)}{kg(solvent)}

Freezing point depression and molal are related as the following:

\Delta T_{f}=K_{f}.m

where

\Delta T_{f} is freezing point depression of solution

K_{f} is molal freezing point depression constant

m is molality

Now, to determine molar mass, first, find molality of the mixture:

\Delta T_{f}=K_{f}.m

m=\frac{\Delta T_{f}}{K_{f}}

For benzene, constant is 5.12°C/molal. Then

m=\frac{3.5}{5.12}

m = 0.683 molal

Second, knowing the relationship between molal and moles of solute, determine the last one:

m=\frac{moles(solute)}{kg(solvent)}

mol(solute)=m.kg(solvent)

mol(solute) = 0.683(0.065)

mol(solute) = 0.044 mol

The definition for <u>Molar</u> <u>mass</u> is the mass in grams of 1 mol of substance:

n(moles)=\frac{m(g)}{MM(g/mol)}

MM=\frac{m}{n}

In the mixture, there are 0.044 moles of X, so its molecular mass is

MM=\frac{2.1}{0.044}

MM = 47.30 g/mol

The molecular compound X has molecular mass of 47.30 g/mol.

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3 years ago
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Answer:

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Explanation:

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134 g C6H12O6 ( 1 mol / 180.18 g ) = 0.744 mol <span>C6H12O6</span>
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