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3 years ago

I really really need help someone!! )):

Mathematics

1 answer:

yaroslaw [1]3 years ago

3 0

diameter is 15 meters then radius is 15/2 = 7.5 meters

so the amplitude is 7.5 m and height will oscillate with amplitude 7.5 m above and below the center.

midline of the oscillation will be 7.5 m

the wheel.take 8 minutes to complete revolution then it means the height will oscillate with a period of 8 minutes

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Step-by-step explanation:

78.25 * .20 = 15.65 as a tip,

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If Triangle ABC= triangle DEF, which statement must be true?

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The statement must be true is AC = DF ⇒ A

Step-by-step explanation:

When two triangles are congruent, then

Their corresponding sides are equal in lengths
Their corresponding angles are equal in measures
Their perimeters and areas are equal

∵ ΔABC ≅ DEF

- Their corresponding sides and angles are equal

∴ AB = DE ⇒ AB is the corresponding side of DE

∴ BC = EF ⇒ BC is the corresponding side of EF

∴ AC = DF ⇒ AC is the corresponding side of DF

∴ ∠A ≅ ∠D ⇒ ∠A is the corresponding angle of ∠D

∴ ∠ABC ≅ ∠DEF ⇒ ∠ABC is the corresponding angle of ∠DEF

∴ ∠C ≅ ∠F ⇒ ∠C is the corresponding angle of ∠F

- Look to the answer to find the correct statement

∴ AC = DF

The statement must be true is AC = DF

Learn more:

You can learn more about the congruent of triangles in brainly.com/question/6108628

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2 years ago

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Answer:

Part A: The temperature must be greater than -40, and lower than 140. -40 < T < 140

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2 years ago

Solve the following quadratic by completing the square. y = x^2 - 6x+7

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Answer:

$x= 3+\sqrt{2}, \quad x= 3 -\sqrt{2}$

Step-by-step explanation:

Given quadratic equation:

$y = x^2 - 6x+7$

To complete the square, begin by adding and subtracting the square of half the coefficient of the term in x:

$\implies y = x^2 - 6x+\left(\dfrac{-6}{2}\right)^2-\left(\dfrac{-6}{2}\right)^2+7$

$\implies y = x^2 - 6x+\left(-3\right)^2-\left(-3\right)^2+7$

$\implies y = x^2 - 6x+9-9+7$

Factor the perfect square trinomial:

$\implies y=(x-3)^2-9+7$

$\implies y=(x-3)^2-2$

To solve the quadratic, set it to zero and solve for x:

$\implies (x-3)^2-2=0$

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Therefore, the solution to the given quadratic equation is:

$x= 3+\sqrt{2}, \quad x= 3 -\sqrt{2}$

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9 months ago

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