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erica [24]
2 years ago
12

What is 4 3/5 multiplied by 3 1/5 as a mixed number or fraction

Mathematics
2 answers:
nikklg [1K]2 years ago
8 0

Answer:

14 18/25 is the answer

Step-by-step explanation:

23/5 x 16/5

23x16

5x5

368/25=14 18/25

sashaice [31]2 years ago
3 0

Answer:

14 18/25 .

Step-by-step explanation:

4 3/5 =  (5*4 + 3)/ 5 = 23/5

3 1/5 = (5*3 + 1) / 5 =   16/5

23/5 * 16/5

= 368 / 25

= 14  18/25  (answer).

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Consider the differential equation <img src="https://tex.z-dn.net/?f=%20x%5E%7B2%7D%20%20%5Cfrac%7Bdy%7D%7Bdx%7D%20%3D6%20y%5E%7
Nutka1998 [239]
As a Bernoulli equation:

x^2\dfrac{\mathrm dy}{\mathrm dx}=6y^2+6xy\iff x^2y^{-2}\dfrac{\mathrm dy}{\mathrm dx}-6xy^{-1}=6

Let z=y^{-1}\implies\dfrac{\mathrm dz}{\mathrm dx}=-y^{-2}\dfrac{\mathrm dy}{\mathrm dx}. The ODE becomes

-x^2\dfrac{\mathrm dz}{\mathrm dx}-6xz=6
x^6\dfrac{\mathrm dz}{\mathrm dx}+6x^5z=-6x^4
\dfrac{\mathrm d}{\mathrm dx}[x^6z]=-6x^4
x^6z=-6\displaystyle\int x^4\,\mathrm dx
x^6z=-\dfrac65x^5+C
z=-\dfrac6{5x}+\dfrac C{x^6}
y^{-1}=-\dfrac6{5x}+\dfrac C{x^6}
y=\dfrac1{\frac C{x^6}-\frac6{5x}}
y=\dfrac{5x^6}{C-6x^5}

With y(3)=6, we get

6=\dfrac{5(3)^6}{C-6(3)^5}\implies C=\dfrac{4131}2

so the solution is

y=\dfrac{5x^6}{\frac{4131}2-6x^5}=\dfrac{10x^6}{4131-12x^5}

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3 years ago
Can you identify a parallel or perpendicular equation and type the correct code?
Lady_Fox [76]

Answer:

1) C. -3/4·x + 3

2) E. 3/4·x - 1

3) I. -2/5·x + 3

4) A. 2/5·x - 1

Step-by-step explanation:

1) The points on the given line are;

(4, -2), (0, 1), and (-4, 4)

The slope of the line = (1 - (-2))/(0 - 4) = -3/4

The y-intercept = (0, 1)

The equation of the line is therefore, y = -3/4·x + 1

The line parallel to the given line has equal slope to the line, and the different y-intercept, therefore, the correct option for the line parallel to the given line is therefore;

C. -3/4·x + 3

2) The equation of the given line is 4·x + 3·y = 12

Rewriting the equation in slope and intercept form gives;

4·x + 3·y = 12

3·y = 12 - 4·x

y = 12/3 - 4/3·x = 4 - 4/3·x

The slope, m₁, of the given line = -4/3

The y-intercept = (0, 4)

A line perpendicular to the given line, has a slope, m₂ = -1/m₁

Where, m₁ = The slope of the given line

The slope of the perpendicular to the given line is therefore;

m₂ = -1/m₁ = -1/(-4/3) = 3/4

Therefore, the equation of the line perpendicular to the given line is of the form

y =  3/4·x + c, where c is a real number

The correct option for the line perpendicular to the given line is therefore; E. 3/4·x - 1

3) The equation of the given line is 2·x + 5·y = 10

Rewriting the equation in slope and intercept form gives;

2·x + 5·y = 10

5·y = 10 - 2·x

y = 10/5 - 2/5·x = 2 - 2/5·x

y = 2 - 2/5·x

The slope, m₂, of a parallel line to the given line is equal to that of the given line, m₁

Whereby from the above equation, we have, m₁ = -2/5

Therefore, m₂ = m₁ = -2/5

The general equation of a line parallel to the given line is therefore;

y = m₂·x + c = -2/5·x + c, where c is a real number

The correct option for the line parallel to the given line is therefore;

I. -2/5·x + 3

4) The points (intercepts) on the given line are (2, 0), and (0, 5)

The slope of the given line is therefore;

(5 - 0)/(0 - 2) = -5/2

The slope of the perpendicular line, m₂ = -1/m₁, gives;

m₂ = -1/(-5/2) = 2/5

The general form equation of the equation of the perpendicular line to the given line is therefore given as follows;

y = m₂·x + c = 2/5·x + c, where c is a real number

The correct option for the line perpendicular to the given line is therefore;

A. 2/5·x - 1.

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2 years ago
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Tju [1.3M]

Answer:

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Step-by-step explanation:

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