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grandymaker [24]
3 years ago
6

y + 7 = - 2/5 * (x - 10) . What is theThe point-slope of the equation of the line that passes through (- 5, - 1) and (10, - 7) i

s standard form of the equation for this line? 2x - 5y = - 15 2x - 5y = - 17 2x + 5y = - 15 2x + 5y = - 17
Mathematics
1 answer:
a_sh-v [17]3 years ago
7 0

Answer:

The Standard Form of the Equation is A. 2x - 5y = -15

Step-by-step explanation:

Given points: (-5, -1) and (10, -7).

Find the slope:

m = (y - y1)/(x - x1)

= -1 - (-7)/-5 - 10

= -1 + 7/-15

= 6/-15

m = -2/5

You already had the point slope form:

y - y1 = m(x - x1)

y - (-7) = -2/5(x - 10)

y + 7 = -2/5(x - 10)

The rest of the question is looking for the standard form of the equation:

Ax + By = C

Begin by solving the point slope form for y:

y + 7 = -2/5x + 20/5

y + 7 = -2/5x + 4

y = -2/5x - 3

Now, put the equation into the standard form:

y + 2/5x = -3

Multiply by 5, and place x first:

2x + 5y = -15, the Standard form of the Equation

Prove by setting x = 0 and finding the y intercept:

5y + 2(0) = -15

5y = -15

y = -3, giving the y intercept, when x = 0 as -3 or (0, -3)

Hope this helps!! Have an Awesome Day!!  :-)

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Answer:

8 students

Step-by-step explanation:

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Please mark as Brainliest.

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3 years ago
Which has a greater slope, a horizontal line or a vertical line?
AfilCa [17]

Answer:

A

Step-by-step explanation:

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6 0
3 years ago
Identify the radius and center.<br><br> x^2 + y^2 - 2x + 4y - 11 = 0
miss Akunina [59]
<h2>Hello!</h2>

The answer is:

Center: (1,-2)

Radius: 4 units.

<h2>Why?</h2>

To solve the problem, using the given formula of a circle, we need to find its standard equation form which is equal to:

(x-h)^{2}+(y-k)^{2}=r^{2}

Where,

"h" and "k"are the coordinates of the center of the circle and "r" is its radius.

So, we need to complete the square for both variable "x" and "y".

The given equation is:

x^2+y^2-2x+4y-11=0

So, solving we have:

x^2+y^2-2x+4y=11

(x^2-2x+(\frac{2}{2})^{2} )+(y^2+4y+(\frac{4}{2})^{2})=11+(\frac{2}{2})^{2} +(\frac{4}{2})^{2}\\\\(x^2-2x+1)+(y^2+4y+4)=11+1+4\\\\(x^2-1)+(y^2+2)=16

(x^2-1)+(y^2-(-2))=16

Now, we have that:

h=1\\k=-2\\r=\sqrt{16}=4

So,

Center: (1,-2)

Radius: 4 units.

Have a nice day!

Note: I have attached a picture for better understanding.

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Answer:

-0.5

Step-by-step explanation:

5+8=13

13/2=6.5

6.5-7=-0.5

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