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olga_2 [115]
3 years ago
15

Solve 8x + c = k for x

Mathematics
2 answers:
SIZIF [17.4K]3 years ago
6 0

Answer:

x = \frac{k-c}{8}

Step-by-step explanation:

Solve:

8x+c = k

Subtract c from both sides we have;

8x+c-c= k-c

Simplify:

8x = k-c

Divide both sides by 8 we have;

x = \frac{k-c}{8}

Therefore, the value of x is, \frac{k-c}{8}

mr Goodwill [35]3 years ago
3 0
Ok so this is how you do it.....
You need to get x by itself.
8x + c = k
Subtract c.
8x = k - c
Divide 8 from both sides.
x = k - c / 8
I hope this helps love! :)
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If 2x<br> + 13x – 7 = 0, then x could equal to which of the following?
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Answer:

7 / 15

Step-by-step explanation:

15x - 7 = 0

15x = 7

x = 7/15

7 0
3 years ago
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Given loga (m) = 10 and loga (n) = 25 , find loga (m * n ^ 2)
mina [271]

The result of the log function log_a (m * n ^ 2)  is 60

According to the law of logarithm if log_ab=y then b=a^y

Given the following expressions

log_am=10\\log_an=25

This can be expressed as

m =a^{10} \ and \ n = a^{25}

Substitute the value of m and n into the expression log_a (m * n ^ 2) to have:

log_a (m * n ^ 2) = log_a(a^{10}\times a^{50})\\=log_aa^{60}\\=60log_aa\\=60(1) \\= 60

This shows that the result of the log function log_a (m * n ^ 2)  is 60

Learn more here: brainly.com/question/12049968

6 0
2 years ago
How do u write 3:4 and 6:8 as a fraction proportion
faltersainse [42]

3/4=6/8

hope this helps :)

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2 years ago
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Q2) The following travel times were measured for vehicles traversing a 2,000 ft. segment of an arterial: Vehicle Travel Time (s)
adelina 88 [10]

Answer:

TMS = 45.78 m/s

SMS = 45.66 m/s

Step-by-step explanation:

Vehicle Travel Time (s)

1 40.5

2 44.2

3 41.7

4 47.3

5 46.5

6 41.9

7 43.0

8 47.0

9 42.6

10 43.3

Time mean speed and space mean speed are parameters used to express the speed of a group of vehicles in traffic flow.

Time mean speed is given as the average speed of all the cars

The speed for each vehicle is calculated by dividing the (2000 ft) distance by the time taken by each vehicle to complete that segment of the journey.

Let vehicle = V

Travel time = time

Speed = s

V | Time | speed (ft/s)

1 | 40.5 | 49.383

2 | 44.2 | 45.249

3 | 41.7 | 47.962

4 | 47.3 | 42.283

5 | 46.5 | 43.011

6 | 41.9 | 47.733

7 | 43.0 | 46.512

8 | 47.0 | 42.553

9 | 42.6 | 46.948

10| 43.3 | 46.189

TMS = (Σsᵢ)/N

Σsᵢ = (49.383+45.249+47.962+42.283+43.011+47.733+46.512+42.553+46.948+46.189)

Σsᵢ = 457.823

N = number of vehicles = 10

TMS = 457.823 ÷ 10 = 45.7823 = 45.782 m/s

b) Space mean speed is given as

SMS = N ÷ [Σ (1/sᵢ)]

V | Time | speed | (1/sᵢ)

1 | 40.5 | 49.383 | 0.02025

2 | 44.2 | 45.249 | 0.02210

3 | 41.7 | 47.962 | 0.02085

4 | 47.3 | 42.283 | 0.02365

5 | 46.5 | 43.011 | 0.02325

6 | 41.9 | 47.733 | 0.02095

7 | 43.0 | 46.512 | 0.02150

8 | 47.0 | 42.553 | 0.02350

9 | 42.6 | 46.948 | 0.02130

10| 43.3 | 46.189 | 0.02165

Σ (1/sᵢ) = (0.02025+0.02210+0.02085+0.02365+0.02325+0.02095+0.02150+0.02350+0.02130+0.02165)

Σ (1/sᵢ) = 0.219

SMS = 10 ÷ [Σ (1/sᵢ)] = 10 ÷ 0.219

SMS = 45.662 m/s

Hope this Helps!!!

4 0
3 years ago
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