Its factors would be
(x+2)*(x-1)*(x+0)
x^2 +x -2
x^3 + 0 + x^2 + 0 -2x +0
Equation: x^3 + x^2 -2x
f(2) = 8 + 4 -4
2x^3 + 2x^2 -4x +0
f(2) = 16 + 8 -8
3x^3 + 3x^2 -6x +0
f(2) = 24 +12 -12
4x^3 + 4x^2 -8x +0
f(2) = 32 +16 -16
So, the equation is:
4x^3 + 4x^2 -8x = 0
H = –16t2 + 156t + 105, when t = t', the time where the rocket hit the ground after it is launched, so 105= –16t'2 + 156t' + 105, so -16t'2 + 156t' = 0 implies t' =0 or -16t'+ 156= 0, equivalent to t'=9.75, so the answer is
b) <span>9.8 s</span>
Thx tahayahahataghaahtsyaha
The place value of 1 is hundred thousands.
Do (10 x 10) then (10 x 20), and then add your two answers together.
Its simple :)