Ask question

Ask question

All categories

3 years ago

7

What best describes the degree to which a material can transmit Heat A:melting point B:boiling point C: thermal conductivity D:

electrical conductivity

2 answers:

Oduvanchick [21]3 years ago

7 0

Your answer is going to be C

3241004551 [841]3 years ago

7 0

C. Thermal Conductivty

You might be interested in

15.0 mL of an unknown clear liquid is added to a 50 mL graduated cylinder. The mass of the liquid is determined to be 12.7 grams

sveticcg [70]

Answer:

$\boxed {\tt A. \ d=0.85 \ g/mL}$

Explanation:

Density is found by dividing the mass by the volume.

$d=\frac{m}{v}$

The mass of the liquid is 12.7 grams.

We know that 15 mL of this liquid was added to a 50 mL graduated cylinder. Therefore, the volume is 15 mL. The 50 mL is not relevant, it only tells us about the graduated cylinder.

$m= 12.7 \ g\\v= 15 \ mL$

Substitute the values into the formula.

$d=\frac{12.7 \ g}{ 15 mL}$

Divide.

$d=0.846666667 \ g/mL$

Round to the nearest hundredth. The 6 in the tenth place tells us to round the 4 to a 5.

$d \approx 0.85 \ g/mL$

The density of the liquid is about 0.85 grams per milliliter and choice A is correct.

4 0

3 years ago

What are the four phases of matter?

user100 [1]

Solid, Liquid, Gas, and Plasma

6 0

2 years ago

Read 2 more answers

Write a net ionic equation for the overall reaction that occurs when aqueous solutions of hydrosulfuric acid (H2S) and sodium hy

vovangra [49]

Answer: 2NH4Br(aq)+Pb(C2H302(aq)-------------------->

2NH4C2H3o2(aq) + PbBr2(s)

Explanation:

The net equation is :Pb2+ (aq)2Br (aq)---------------------->PbBr2(s)

the spectator ions NH4 +C2H3O2 are canceled

6 0

3 years ago

What amount of moles of sodium chloride is needed to prepare 1.25 L of a salt solution with a concentration of 0.750 mol/L

stellarik [79]

Answer:

Number of moles = 0.94 mol

Explanation:

Given data:

Number of moles of sodium chloride = ?

Volume of sodium chloride = 1.25 L

Concentration of solution = 0.750 mol/L

Solution:

Formula:

Concentration = number of moles/ volume in L

By putting values.

0.750 mol/L = number of mole / 1.25 L

Number of moles = 0.750 mol/L×1.25 L

Number of moles = 0.94 mol

4 0

2 years ago

RATE LAW QUESTION !

vivado [14]

In general, we have this rate law express.:

$\mathrm{Rate} = k \cdot [A]^x [B]^y$
we need to find x and y

ignore the given overall chemical reaction equation as we only preduct rate law from mechanism (not given to us).

then we go to compare two experiments in which only one concentration is changed

compare experiments 1 and 4 to find the effect of changing [B]
divide the larger [B] (experiment 4) by the smaller [B] (experiment 1) and call it Δ[B]

Δ[B]= 0.3 / 0.1 = 3

now divide experiment 4 by experient 1 for the given reaction rates, calling it ΔRate:

ΔRate = 1.7 × 10⁻⁵ / 5.5 × 10⁻⁶ = 34/11 = 3.090909...

solve for y in the equation $\Delta \mathrm{Rate} = \Delta [B]^y$

$3.09 = (3)^y \implies y \approx 1$

To this point, $\mathrm{Rate} = k \cdot [A]^x [B]^1$

do the same to find x.
choose two experiments in which only the concentration of B is unchanged:

Dividing experiment 3 by experiment 2:
Δ[A] = 0.4 / 0.2 = 2
ΔRate = 8.8 × 10⁻⁵ / 2.2 × 10⁻⁵ = 4

solve for x for $\Delta \mathrm{Rate} = \Delta [A]^x$

$4= (2)^x \implies x = 2$

the rate law is

Rate = k·[A]²[B]

6 0

3 years ago