Answer:
16
Step-by-step explanation:
10 · 4 = 40
640/40= 16
Answer:
The value of the expression given is:
Step-by-step explanation:
First, you must divide the expression in three, and to the final, you can multiply it:
- [(3^8)*(2^(-5))*(9^0)]^(-2)
- [(2^(-2))/(3^3)]^4
- 3^28
Now, we can solve each part one by one:
<em>First part.
</em>
- 3^8 = 6561
- 2^(-5) = 0.03125
- 9^0 = 1 (Whatever number elevated to 0, its value is 1)
- (6561 * 0,03125 * 1) = 205.03125
And we elevate this to -2:
- 205.03125^-2 = 2<u>.378810688*10^(-5)</u> or <u>0.00002378810688
</u>
<em>Second part.
</em>
- 2^(-2) = 0.25
- 3^3 = 27
- 0.25 / 27 = 9.259259259 * 10^(-3) or 0.00925925925925
And we elevate this to 4:
- 0.00925925925925^4 = <u>7.350298528 * 10^(-9)</u> or <u>0.000000007350298528
</u>
<em>Third Part.
</em>
- 3^28 = <u>2.287679245 * 10^13</u> or <u>22876792450000</u>
At last, we multiply all the results obtained:
- 0.00002378810688 * 0.000000007350298528 * 22876792450000 = <u>3.999999999999999999</u> approximately <u>4</u>
<u><em>We approximate the value because the difference to 4 is minimal, which could be obtained if we use all the decimals in each result</em></u>.
We have to present the number 41 as the sum of two squares of consecutive positive integers.
1² = 1
2² = 4
3² = 9
4² = 16
5² = 25
16 + 25 = 41
<h3>Answer: 4 and 5</h3>
Other method:
n, n + 1 - two consecutive positive integers
The equation:
n² + (n + 1)² = 41 <em>use (a + b)² = a² + 2ab + b²</em>
n² + n² + 2(n)(1) + 1² = 41
2n² + 2n + 1 = 41 <em>subtract 41 from both sides</em>
2n² + 2n - 40 = 0 <em>divide both sides by 2</em>
n² + n - 20 = 0
n² + 5n - 4n - 20= 0
n(n + 5) - 4(n + 5) = 0
(n + 5)(n - 4) = 0 ↔ n + 5 = 0 ∨ n - 4 =0
n = -5 < 0 ∨ n = 4 >0
n = 4
n + 1 = 4 + 1 = 5
<h3>Answer: 4 and 5.</h3>
Answer:
3489.9583
Step-by-step explanation:
but htts its s
Answer: Yes
Step-by-step explanation:
Each value of y maps onto one value of x.
