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marissa [1.9K]
3 years ago
13

Sadik Inc.'s bonds currently sell for $1,180 and have a par value of $1,000. They pay a $105 annual coupon and have a 15-year ma

turity, but they can be called in 5 years at $1,100. What is their yield to call (YTC)?

Business
1 answer:
mr Goodwill [35]3 years ago
7 0

Answer:

7.74%

Explanation:

In this question, we use the Rate formula which is shown in the spreadsheet.  

The NPER represents the time period.  

Given that,  

Present value = $1,180

Assuming figure - Future value or Face value = $1,100  

PMT = $105

NPER = 5 years

The formula is shown below:  

= Rate(NPER;PMT;-PV;FV;type)  

The present value come in negative  

So, after solving this, the answer would be 7.74%

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Answer:

a).

  • Labor hours productivity=3.500
  • Multi-factor productivity=2.423

b). The reduction in labor hours per employee per week to achieve this goal=15.735 hours

c). The maximum value that the overhead costs per week can be to ensure the multi-factor productivity is at least 1.257=$21,059.666

Explanation:

a).

  • <em>Step 1: Determine the labor hours productivity</em>

Labor output per week=potential leads×fee

where;

potential leads=5% of potential leads, and potential leads=3,000

potential leads=5%×3,000

potential leads=(5/100)×3,000=150

one-time fee=$70

replacing;

Labor output per week=70×150=$10,500

Labor input per week=cost per hour per employee×number of employees×number of hours worked

where;

cost per hour per employee=$25

number of employees=3

number of hours worked=40

replacing;

Labor input per week=25×3×40=$3,000

Labor hours productivity=labor output per week/labor input per week

Labor hours productivity=10,500/3,000=3.500

  • <em>Step 2: Determine the multi-factor productivity</em>

Multi-factor productivity=Generated fees/(labor cost+material cost+overhead cost)

where;

generated fees=number of employees×potential leads×potential ratio×fee

number of employees=3, potential leads=3,000, potential ratio=5%=5/100=0.05, fee=$70

generated fees=3×3,000×0.05×70=$31,500

Labor cost=$3,000

Material cost=$1,000

Overhead cost=$9,000

Total cost=3,000+1,000+9,000=$13,000

replacing;

Multi-factor productivity=31,500/13,000=2.423

b). Increasing the multi-factor productivity (MP) by 10%

New MP=(110/100)×2.423=2.665

New MP=generated fees/labor cost+material cost+overhead cost

labor cost=cost per hour per employee×number of employees×number of hours worked

where;

cost per hour per employee=$25

number of employees=3

number of hours worked=h

labor cost=25×3×h=75 h

material cost=$1,000

overhead cost=$9,000

generated fees=$31,500

New MP=2.665

replacing;

2.665=31,500/{(75 h)+(1,000)+(9,000)}

2.665=31,500/75 h+10,000

2.665(75 h+10,000)=31,500

199.875 h+26,650=31,500

199.875 h=31,500-26,650

199.875 h=4,850

h=4,850/199.875

h=24.265

New labor hours=24.265 hours per week

Initial labor hours=40 hours per week

Reduction in labor hours=Initial labor hours-new labor hours

Reduction in labor hours=(40-24.265)=15.735

The reduction in labor hours per employee per week to achieve this goal=15.735 hours

c). Using a multi-factor of 1.257

MP=generated fees/labor cost+material cost+overhead cost

where;

MP=1.257

generated fees=$31,500

Labor cost=$3,000

Material cost=$1,000

Overhead cost=c

replacing;

1.257=31,500/(c+3,000+1,000)

1.257=31,500/c+4,000

1.257(c+4,000)=31,500

1.257 c+5,028=31,500

1.257 c=31,500-5,028

1.257 c=26,472

c=26,472/1.257=21,059.666

The maximum value that the overhead costs per week can be to ensure the multi-factor productivity is at least 1.257=$21,059.666

8 0
2 years ago
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