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AVprozaik [17]
4 years ago
5

Can someone please solve this for me?

Mathematics
1 answer:
Elden [556K]4 years ago
7 0
It looks like for this one you just need to use the midpoint formula for (2a,0) and (0,-4b).
To do this, just use the midpoint formula:
{ (x1+x2)/2 , (y1+y2)/2 }
So 2a+0/2 = a,
and 0-4b= -2b.
So the answer is the second one, (a,-2b)
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What is the vertex form of the quadratic equation represented on the table?
sergeinik [125]

Check the picture below, so the parabola looks more or less like so, hmmm with a vertex at (-1 , -4), so, using those values from the table

~~~~~~\textit{vertical parabola vertex form} \\\\ y=a(x- h)^2+ k\qquad \begin{cases} \stackrel{vertex}{(h,k)}\\\\ \stackrel{"a"~is~negative}{op ens~\cap}\qquad \stackrel{"a"~is~positive}{op ens~\cup} \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}

\stackrel{vertex}{\stackrel{h}{-1}~~,~~\stackrel{k}{-4}}\qquad \implies y=a[x-(-1)]^2-4\implies y=a(x+1)^2-4 \\\\\\ \textit{we also know that} \begin{cases} x=2\\ y=14 \end{cases}\implies 14=a(2+1)^2-4\implies 18=9a \\\\\\ \cfrac{18}{9}=a\implies 2=a~\hspace{10em}\boxed{y=2(x+1)^2-4}

7 0
2 years ago
Convert x - 5 = 0 to a polar equation
dolphi86 [110]

Answer:

(

5

,

π

)

Step-by-step explanation:

−

5

=

r

cos

θ

88

[

1

]

0

=

r

sin

θ

8888

[

2

]

Squaring [1] and [2]:

25

=

r

2

cos

2

θ

0

=

r

2

sin

2

θ

Adding [1] and [2]:

25

=

r

2

cos

2

θ

+

r

2

sin

2

θ

Factor:

25

=

r

2

(

cos

2

θ

+

sin

2

θ

)

25

=

r

2

⇒

r

=

±

5

( use

r

=

5

)

4 0
4 years ago
Timothy is writing a survey. how could timothy ask a statistical question? a. he could ask each person in his class who the tall
MrMuchimi
B the answer is B
To create a survey you need a common entity linked to a unique feature
With B…he is able to create a table,draw a graph ,a pie chart and do so
8 0
3 years ago
We love math. Please help
xxTIMURxx [149]

Answer:

B?

Step-by-step explanation:

3 0
4 years ago
Differentiate with respect to x:y= sinh^-1(x^2+1)
Aleks [24]

Answer:

The first derivative of y = \sinh^{-1} (x^{2}+1) is y' = \frac{2\cdot x}{\sqrt{x^{2}+2\cdot x +2}}.

Step-by-step explanation:

We proceed to find the first derivative of y = \sinh^{-1} (x^{2}+1) by explicit differentiation and rule of chain:

y = \sinh^{-1} (x^{2}+1)

y' = \frac{2\cdot x}{\sqrt{(x^{2}+1)^{2}+1}}

y' = \frac{2\cdot x}{\sqrt{x^{2}+2\cdot x +2}}

The first derivative of y = \sinh^{-1} (x^{2}+1) is y' = \frac{2\cdot x}{\sqrt{x^{2}+2\cdot x +2}}.

8 0
3 years ago
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