Can someone please solve this for me?

Mathematics

1 answer:

Elden [556K]4 years ago

7 0

It looks like for this one you just need to use the midpoint formula for (2a,0) and (0,-4b).
To do this, just use the midpoint formula:
{ (x1+x2)/2 , (y1+y2)/2 }
So 2a+0/2 = a,
and 0-4b= -2b.
So the answer is the second one, (a,-2b)

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we could use the proportions of those small, medium and large similar triangles like $\bf \cfrac{small}{large}\qquad \cfrac{x}{12}=\cfrac{6}{x}\impliedby \textit{solve for "x"}
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$\bf \cfrac{large}{medium}\qquad \cfrac{x+10}{2\sqrt{30}}=\cfrac{2\sqrt{30}}{10}\impliedby \textit{solve for "x"}
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\textit{now, because you already know what "x" is, we can use it below}
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