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AVprozaik [17]
3 years ago
5

Can someone please solve this for me?

Mathematics
1 answer:
Elden [556K]3 years ago
7 0
It looks like for this one you just need to use the midpoint formula for (2a,0) and (0,-4b).
To do this, just use the midpoint formula:
{ (x1+x2)/2 , (y1+y2)/2 }
So 2a+0/2 = a,
and 0-4b= -2b.
So the answer is the second one, (a,-2b)
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Rom4ik [11]

Answer : 2√3

<u>Given </u><u>:</u><u>-</u>

  • A equilateral triangle with side length 4.

<u>To </u><u>Find</u><u> </u><u>:</u><u>-</u>

  • The value of x in the given figure.

As we know that in a equilateral triangle , perpendicular bisector , angle bisector and median coincide with each other .

  • So the perpendicular drawn in the figure will bisect the given side .
  • Therefore the value of each half will be 4/2 = 2 .

Now we may use Pythagoras theorem as ,

→ AB² = BC² + AC²

→ 4² = 2² + x²

→ 16 = 4 + x²

→ x² = 16-4

→ x² = 12

→ x =√12 = √{ 3 * 2²}

→ x = 2√3

<u>Hence </u><u>the</u><u> required</u><u> answer</u><u> is</u><u> </u><u>2</u><u>√</u><u>3</u><u> </u><u>.</u>

I hope this helps.

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