All categories

1 year ago

Hi I’m I don’t understand a variable of what this is saying.

Mathematics

1 answer:

Papessa [141]1 year ago

7 0

given expression to simplify,

$q^{-3}r^0s^{-1}\cdot\: q^3r^{-9}s^0$ $\begin{gathered} q^{-3}r^0s^{-1}\cdot\: q^3r^{-9}s^0 \\ q^{-3}\cdot q^3=1 \\ \: =r^0s^{-1}r^{-9}s^0 \\ =1\cdot\frac{1}{r^9}s^{-1}s^0 \\ =1\cdot\frac{1}{r^9}\cdot\frac{1}{s} \\ =\frac{1}{r^9}\cdot\frac{1}{s} \\ =\frac{1}{r^9s} \\ =r^{-9}s^{-1} \end{gathered}$

You might be interested in

A flower bed has a shape of a rectangle 9yards long and 3 yarss wide what is the area in square feet

Maslowich

It should be 81 square feet.

3 yards x 9 yards = 27 yards squares.

It asks for your answer in square feet, so you multiply by 3. This is because there are 3 feet in ever yard.

27 x 3 feet = 81 square feet.

8 0

2 years ago

Question 1 Unsaved

Andrew [12]

The average of the given base lengths is the length of the midsegment:

... (72 + 104)/2 = 176/2 = 88

8 0

2 years ago

What is 5 minus 16 tenths

antoniya [11.8K]

The answer would be 3.4

Hope that helped : )

5 0

3 years ago

Read 2 more answers

30 points!!<br> What is the sum of the first six terms of the series?<br> 48 - 12 + 3 - 0.75 +...

Lunna [17]

Answer:

The sum of the first six terms is 38.39

Step-by-step explanation:

This is a geometric sequence since the common difference between each term is $-\frac{1}{4}$

Thus, $r=-\frac{1}{4}$

To find the sum of first six terms, we need to find the fifth and sixth term of the sequence.

To find the fifth term:

The general form of geometric sequence is $a_{n}=a_{1} \cdot r^{n-1}$

To find the fifth term, substitute $n=5$ in $a_{n}=a_{1} \cdot r^{n-1}$

$\begin{aligned}a_{5} &=(48) \cdot\left(-\frac{1}{4}\right)^{5-1} \\&=(48) \cdot\left(-\frac{1}{4}\right)^{4} \\&=(48)\left(\frac{1}{256}\right) \\a_{5} &=0.1875\end{aligned}$

To find the sixth term, substitute $n=6$ in $a_{n}=a_{1} \cdot r^{n-1}$

$\begin{aligned}a_{6} &=(48) \cdot\left(-\frac{1}{4}\right)^{6-1} \\&=(48) \cdot\left(-\frac{1}{4}\right)^{5} \\&=(48)\left(-\frac{1}{1024}\right) \\a_{5} &=-0.046875\end{aligned}$

To find the sum of the first six terms:

The general formula to find Sn for $|r|$ is $S_{n}=\frac{a\left(1-r^{n}\right)}{1-r}$

$\begin{aligned}S_{6} &=\frac{48\left(1-\left(-\frac{1}{4}\right)^{6}\right)}{1-\left(-\frac{1}{4}\right)} \\&=\frac{48\left(1-\frac{1}{4096}\right)}{1+\frac{1}{4096}} \\&=\frac{48(0.95)}{5} \\&=\frac{48(0.9998)}{5} \\&=\frac{48(0.9998)}{5} \\&=\frac{47.9904}{5} \\&=38.39\end{aligned}$

Thus, the sum of first six terms is 38.39

5 0

2 years ago

Event the die comes up at most 2

hjlf

X. 1. 2. 3. 4. 5. 6 are all the possible events when rolling a die. If it is a fair die then the probability of rolling any number is 1/6. So the probability of rolling at most a two is p(1)+ p(2)= 2/6 or 1/3

4 0

3 years ago