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STALIN [3.7K]
3 years ago
14

Which substance has the highest ignition​ temperature?

Chemistry
1 answer:
erica [24]3 years ago
7 0
It will be  a. <span>benzene.</span>
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A person buildirig an aquarium would benefit from adding a livce rock to their aquarium because ?
spayn [35]
It introduces a diverse array of bacteria, algae, and invertebrates to the closed marine environment and functions as a superior biological filter
7 0
3 years ago
Predict products or C3H8 + O2 via combustion
EastWind [94]
When propane   is  burned  in  air  in  a process  known  as  combustion  it  produce   carbon  (IV) oxide  and  water
 the  word  equation  is  as follows,
  propane + oxygen--->carbon (IV)  oxide + water
chemical  equation  is  as follows
  2C3H8  +7O2--->  3CO2  + 8 H2O
hence  2 moles  of propane  reacted with 7  moles  of  oxygen  to  give 3  moles of  CO2  and  8  moles  of  H2o
4 0
3 years ago
What steps would you take in a lab to prepare 1000 mL of a 2 M NaCl solution
amm1812

Answer:

The answer to your question is below

Explanation:

Data

Volume = 1000 ml

Concentration = 2M

molecule = NaCl

Process

1.- Calculate the number of moles of NaCl

Molarity = moles/Volume

-Solve for volume

moles = Molarity x Volume (liters)

-Substitution

moles = 2 x 1

-Result

moles = 2

2.- Determine the molar mass of NaCl

NaCl = 23 + 35.5 = 58.5 g

3.- Calculate the mass of NaCl to prepare the solution

               58.5 g -----------------  1mol

                   x      -----------------  2 moles

                       x = (2 x 58.5) / 1

                       x = 117g

4.- Weight 117 g of NaCl, place them in a volumetric flask (1 l), and add enough water to prepare the solution.

7 0
4 years ago
Which of the following has the greatest effect on colligative properties?
Grace [21]

Answer:

A. Calcium chloride (CaCI2)

7 0
3 years ago
Read 2 more answers
How many moles of caco3 are there in an antacid tablet containing 0.515 g caco3?
MaRussiya [10]
The  moles  of  CaCO3  which  are  there  in  antacid  tablet  that  contain  0.515g  CaCO3  is  calculated  as  follows

moles  =mass/molar  mass

the  molar  mass  of  CaCO3 =  ( 40  x1)+  (12  x  1)  + (16 x  3)=  100  g/mol

moles  is  therefore=  0.515g/100 g/mol=  5.15  x10^-3  moles


8 0
3 years ago
Read 2 more answers
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