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Tems11 [23]
3 years ago
12

The current gold price is $1795 per troy ounce. what is the price of one pound of gold?

Chemistry
1 answer:
GrogVix [38]3 years ago
7 0

<em>1 troy ounce is equal to 0.0685714 pound.</em>

<em>1 pound is equal to 14.5833 troy ounces.</em>

14.5833 x 1795 = 26177.0235

1 pound of gold is approximately $26177.03

<u>Hopefully that helped! :)</u>

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if you take a dried out white rose and place the stem in food coloring, will the rose turn the color you put the stem in
cricket20 [7]

Answer:

Yes, this is true. The reason is that the flower transpires and sucks the water in and distributes it as much as it can. You can also flip it upside down and hang it with petals down , allowing the liquid to enter the flower and then retaining color for longer periods of time and having more color.

Explanation:

7 0
3 years ago
What is the solution to the problem expressed to the correct number of significant figures
quester [9]

I don't know what the problem is, but here are some rues to help you out:

  1. All non-zero figures are significant
  2. When a zero falls between non-zero digits, that zero is significant.
  3. When a zero falls after a decimal point, that zero is significant.
  4. When multiplying and dividing significant figures, the answer is limited to the number of sig figs equal to the least number of sig figs in the problem.
  5. When adding and subtracting, the answer is limited to the number of decimal places in the number with the least number of decimal places.
4 0
3 years ago
Which of the following is a characteristic science?
NikAS [45]

Answer:

what are the answer choices?

Explanation:

6 0
3 years ago
How many sulfur atoms are present in 25.6 g of Al2(S2O3)3
IgorC [24]

Given the mass of Al_{2}(S_{2}O_{3})_{3}=25.6 g

The molar mass of Al_{2}(S_{2}O_{3})_{3}=390.35g/mol

Converting mass of Al_{2}(S_{2}O_{3})_{3}to moles:

25.6 g Al_{2}(S_{2}O_{3})_{3}*\frac{1molAl_{2}(S_{2}O_{3}}{390.35 gAl_{2}(S_{2}O_{3}} =0.0656molAl_{2}(S_{2}O_{3}

Converting mol Al_{2}(S_{2}O_{3})_{3}to mol S:

0.0656mol Al_{2}(S_{2}O_{3})_{3}*\frac{6molS}{1mol Al_{2}(S_{2}O_{3})_{3}}=0.3936 molS

Converting mol S to atoms of S using Avogadro's number:

1 mol = 6.022*10^{23}atoms

0.3936mol S *\frac{6.022*10^{23}atoms S}{1 mol S}=2.37*10^{23} S atoms

5 0
3 years ago
How many mole of ZnCl2 will be produced from 55.0 g of Zn, assuming HCL is available in excess
Ilia_Sergeevich [38]

Answer:

0.84 mol

Explanation:

Given data:

Moles  of ZnCl₂ produced = ?

Mass of Zn = 55.0 g

Solution:

Chemical equation:

2HCl + Zn  →  ZnCl₂ + H₂

Number of moles of Zn:

Number of moles = mass / molar mass

Number of moles = 55.0 g/ 65.38 g/mol

Number of moles = 0.84 mol

Now we will compare the moles of Zn with ZnCl₂ from balance chemical equation.

                                      Zn          :             ZnCl₂

                                         1          :               1

                                      0.84       :           0.84

So from 55 g of Zn 0.84 moles of zinc chloride will be produced.

8 0
3 years ago
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