Answer:
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Explanation:
Answer is: line be long 3,011·10¹³ kilometers.
diametar of virus = 5·10⁻⁶ cm ÷ 100000 = 5·10⁻¹¹ km.
line lenght = 5·10⁻¹¹ km · 6,023·10²³.
line lenght = 3,011·10¹³ km.
Avogadro number = 6,023·10²³.
1 cm = 10⁻² m = 10⁻⁵ km.
Answer:
Mass = 101891.2 g
Explanation:
Given data:
Mass of ammonia needed = ?
Mass of ammonium sulfate produced = 396 Kg = 396 ×1000 = 396000 g
Solution:
Chemical equation:
2NH₃ + H₂SO₄ → (NH₄)₂SO₄
Number of moles of (NH₄)₂SO₄:
Number of moles = mass/molar mass
Number of moles = 396000 g / 132.14 g/mol
Number of moles = 2996.8 mol
Now we will compare the moles of ammonia and ammonium sulfate
(NH₄)₂SO₄ : NH₃
1 : 2
2996.8 : 2/1×2996.8 = 5993.6 mol
Mass of ammonia needed:
Mass = number of moles × molar mass
Mass = 5993.6 mol × 17 g/mol
Mass = 101891.2 g
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