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dem82 [27]
3 years ago
5

Why does the boiling point of water change at high elevation (maybe in Denver, Colorado, the Mile-High City) compared to sea lev

el (maybe in Ocean County, New Jersey)?
Chemistry
1 answer:
Oksanka [162]3 years ago
7 0

Explanation:

This is due to a reduction in atmospheric pressure – pressure due to the weight of the overlying air column). Remember that the higher the altitude the lower the air density and subsequently the lower the air pressure.

Therefore when heating water at higher altitude the vapor pressure of the water at the surface overpowers the atmospheric pressure – which is slightly lower than at sea level – even before the water temperatures reach 100 degrees centigrade.

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Consider the following equilibrium: 4KO2(s) + 2H2O(g) 4KOH(s) + 3O2(g) Which of the following is a correct equilibrium expressio
jeka57 [31]
To be able to write correctly the equilibrium expression of a reaction, we need to know the balanced reaction and the phases of the substances in the reaction. When substances are solid, pure liquid they are not included in the expression. We do as follows:

<span>4KO2(s) + 2H2O(g) = 4KOH(s) + 3O2(g)

K = [O2]^3 / [H2O]^2</span>
5 0
3 years ago
According to the following reaction, how many grams of potassium phosphate will be formed upon the complete reaction of 29.6 gra
Ugo [173]

Answer:

There is 37.36 grams of K3PO4 produced

Explanation:

Step 1: Data given

Mass of H3PO4 = 29.6 grams

KOH is in excess

Molar mass of KOH = 56.11 g/mol

Molar mass of H3PO4 = 97.99 g/mol

Step 2: The balanced equation

3KOH(aq) + H3PO4(aq) ⇔ K3PO4(aq)+3H2O(l)

Step 3: Calculate mass of KOH

Mass KOH = mass KOH / molar mass KOH

Mass KOH = 29.6 grams / 56.11 g/mol

Mass KOH = 0.528 moles

Step 4: Calculate moles of K3PO4

Since KOH is the limiting reactant, We need 3 moles of KOH for each moles of H3PO4, to produce 1 mole of K3PO4 and 3 moles of H2O

For 0.528 moles of KOH we'll have 0.528/3 =  0.176 moles of K3PO4

Step 5: Calculate mass of K3PO4

Mass K3PO4 = moles K3PO4 * molar mass K3PO4

Mass K3PO4 = 0.176 moles * 212.27 g/mol

Mass K3PO4 = 37.36 grams

There is 37.36 grams of K3PO4 produced

8 0
3 years ago
Write empirical formula
andrew11 [14]

Answer:

Pb(ClO_{3})_{4}\\Pb(MnO_{4})_{4}\\Fe(ClO_{3})_{3}\\\Fe(MnO_{4})_{3}\\

Explanation:

Pb^{4+}(ClO_{3}^{-})_{4}--->Pb(ClO_{3})_{4}\\Pb^{4+}(MnO_{4}^{-})_{4}--->Pb(MnO_{4})_{4}\\Fe^{3+}(ClO_{3}^{-})_{3}--->Fe(ClO_{3})_{3}\\\Fe^{3+}(MnO_{4}^{-})_{3}--->Fe(MnO_{4})_{3}\\

3 0
3 years ago
3.0 L of oxygen gas is heated from 100k to 250k. What is the new volume after the temperature has been increased???
alexandr402 [8]

Answer:

7.5 L

Explanation:

Using Charles' law, which is V1/T1=V2/T2, we can plug in these numbers to find the answer.  The law states that volume is directly proportional to temperature. 3.0L/100K = x L / 250 K. Solve for x to get 7.5 L. Hope this helps.

7 0
3 years ago
What is the number of electrons that can be held in the first orbit closest to the nucleus
Juliette [100K]
The first shell can hold up to 2 electrons, the second shell can hold up to 8 (2 + 6) electrons, the third shell can hold up to 18 (2 + 6 + 10) and so on.
5 0
3 years ago
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