Answer:
The answer is cosx cot²x ⇒ the first answer
Step-by-step explanation:
∵ cot²x = cos²x/sin²x
∵ secx = 1/cosx
∴ cot²x secx - cosx = (cos²x/sin²x)(1/cosx) - cosx
= (cosx/sin²x) - cosx
Take cosx as a common factor
∴ cosx[(1/sin²x) - 1] ⇒ use L.C.M
∴ cosx[1-sin²x/sin²x]
∵ 1 - sin²x = cos²x
∴ cosx(cos²x/sin²x) = cosx cot²x
50 dollars per month. It says "after x months" -50x is the variable thats changes.
The answer is C. -<span>3 3/4, -2 1/4, 1 1/8
It is because the highest number in the negatives, -3 3/4, is always the lowest. Obviously if there is no negative sign it is positive. 1 1/8 is the only positive so it is the greatest. And -2 1/4 is lower that -3 3/4. So it is higher than -3 3/4 but lower than 1 1/8.
I'm sorry I'm not the best explainer, but does this help?</span>
<span>(2x-3)/x^2
if the number is –2
then
[2(-2) - 3] / (-2)^2
= (-4-3)/4
= -7/4
answer is
</span><span>D. -7/4</span>
<h2>
Answer:</h2>
The ratio of the area of region R to the area of region S is:

<h2>
Step-by-step explanation:</h2>
The sides of R are in the ratio : 2:3
Let the length of R be: 2x
and the width of R be: 3x
i.e. The perimeter of R is given by:

( Since, the perimeter of a rectangle with length L and breadth or width B is given by:
)
Hence, we get:

i.e.

Also, let " s " denote the side of the square region.
We know that the perimeter of a square with side " s " is given by:

Now, it is given that:
The perimeters of square region S and rectangular region R are equal.
i.e.

Now, we know that the area of a square is given by:

and

Hence, we get:

and

i.e.

Hence,
Ratio of the area of region R to the area of region S is:
