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KIM [24]
3 years ago
12

F(9) if f (x)=5x-16, what is the answer to the math problem

Mathematics
1 answer:
Anastasy [175]3 years ago
3 0
F(9)
sub 9 forx
f(9)=5(9)-16
f(9)=45-16
f(9)=29

f(9)=29
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Simplify the following expression.
AlekseyPX

Answer:

The answer is cosx cot²x ⇒ the first answer

Step-by-step explanation:

∵ cot²x = cos²x/sin²x

∵ secx = 1/cosx

∴ cot²x secx - cosx = (cos²x/sin²x)(1/cosx) - cosx

  = (cosx/sin²x) - cosx

Take cosx as a common factor

∴ cosx[(1/sin²x) - 1] ⇒ use L.C.M

∴  cosx[1-sin²x/sin²x]

∵ 1 - sin²x = cos²x

∴ cosx(cos²x/sin²x) = cosx cot²x

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Which lists show numbers ordered from least to greatest? Choose all that apply.
saw5 [17]
The answer is C. -<span>3 3/4, -2 1/4, 1 1/8 

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7 0
4 years ago
Evaluate the expression described below if the number is –2. The quotient of three less than twice a number and the number squar
lozanna [386]
<span>(2x-3)/x^2 
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then
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4 0
3 years ago
The perimeters of square region S and rectangular region R are equal. If the sides of R are in the ratio 2 : 3, what is the rati
Ksivusya [100]
<h2>Answer:</h2>

The ratio of the area of region R to the area of region S is:

                    \dfrac{24}{25}

<h2>Step-by-step explanation:</h2>

The sides of R are in the ratio : 2:3

Let the length of R be: 2x

and the width of R be: 3x

i.e. The perimeter of R is given by:

Perimeter\ of\ R=2(2x+3x)

( Since, the perimeter of a rectangle with length L and breadth or width B is given by:

Perimeter=2(L+B) )

Hence, we get:

Perimeter\ of\ R=2(5x)

i.e.

Perimeter\ of\ R=10x

Also, let " s " denote the side of the square region.

We know that the perimeter of a square with side " s " is given by:

\text{Perimeter\ of\ square}=4s

Now, it is given that:

The perimeters of square region S and rectangular region R are equal.

i.e.

4s=10x\\\\i.e.\\\\s=\dfrac{10x}{4}\\\\s=\dfrac{5x}{2}

Now, we know that the area of a square is given by:

\text{Area\ of\ square}=s^2

and

\text{Area\ of\ Rectangle}=L\times B

Hence, we get:

\text{Area\ of\ square}=(\dfrac{5x}{2})^2=\dfrac{25x^2}{4}

and

\text{Area\ of\ Rectangle}=2x\times 3x

i.e.

\text{Area\ of\ Rectangle}=6x^2

Hence,

Ratio of the area of region R to the area of region S is:

=\dfrac{6x^2}{\dfrac{25x^2}{4}}\\\\=\dfrac{6x^2\times 4}{25x^2}\\\\=\dfrac{24}{25}

6 0
3 years ago
Read 2 more answers
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