What is the distance between (3, 7 and (15, 16)

1 answer:

4 0

D = √( (x2 - x1)^2 + (y2 - y1)^2 )
D = √( (15-3)^2 + (16 - 7)^2 )
D = √ ( 12^2 + 9^2 )
D = √ (144 + 81)
D = √225
D = 15

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