Solution:
Number of times a die is rolled = 20
1 - 3=A
2 - 5=B
3 - 4=C
4 - 2=D
5 - 3=E
6 - 3=F
Total number of arrangements of outcomes , when a dice is rolled 20 times given that 1 appear 3 times, 2 appears 5 times, 3 appear 4 times, 4 appear 2 times , 5 appear three times, and 6 appear 3 times
= Arrangement of 6 numbers (A,B,C,D,E,F) in 6! ways and then arranging outcomes
= 6! × [ 3! × 5! × 4!×2!×3!×3!]
= 720 × 6×120×24×72→→[Keep in Mind →n!= n (n-1)(n-2)(n-3)........1]
= 895795200 Ways
Sin ø = opposite/hypotenuse = 2/3, cos ø = adjacent/hypotenuse = ?/3, tan ø = opposite/adjacent = 2/?, sec ø = 1/cos ø
to solve ?, Pythagorean theorem must be applied
hypotenuse^2 = adjacent^2 + opposite^2
Manipulating the equation to find the adjacent value = ?
adjacent = sqrt(hypotenuse^2 - opposite^2) = sqrt(9-4)
adjacent = sqrt(5)
so cos ø = sqrt(5)/3, tan ø = 2/sqrt(5) and sec <span>ø = 3/sqrt(5) since the value is positive the possible equivalent trigonometric function should be positive, the answer should be b </span>
Answer:
I am trying to help you, but i need to know the content of the question. What am i trying to do? Simplify? Explain? Say if true or False? More info will allow me to assist you much better than before. Then I will alter my answer accordingly
Step-by-step explanation: