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Anton [14]
3 years ago
9

Describe why there are the same numbers of particles in the beginning and at the end of the reaction of iron sulphide

Chemistry
1 answer:
tankabanditka [31]3 years ago
4 0
You still have the same mass <span>because you haven't created or destroyed anything.

Hope this helps :)

</span>
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What is the instantaneous rate of formation of product C given the following information: a. Stoichiometric equation A+ B2C+ D b
quester [9]

Answer:

1.728 mol /(L*min)

Explanation:

Hello,

In the attached photo, you'll find the numerical procedure for your question.

- Take into account that the negative sign is eligible for reagents and positive for products.

Best regards!

6 0
3 years ago
Sulfuric acid is a component of acid rain formed when gaseous sulfur dioxide pollutant reacts with gaseous oxygen and liquid wat
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2SO₂(g) + O₂(g) + 2H₂O(aq) → 2H₂SO₄(aq)
6 0
3 years ago
Read 2 more answers
Which of the following compounds contains the lead (iv) ion?
Oliga [24]
Oxidation state of Pb in PbO2 is +4.
Oxidation state of Pb in PbCl2 is +2.
Oxidation state of Pb in Pb2O is +1.
Oxidation state of Pb in Pb4O3 is +6/4.

Hence option A. PbO2 is correct.
Hope this helps, have a nice day!
6 0
3 years ago
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How does more greenhouse gases in the Earth's atmosphere affect earth's temperature?
Mumz [18]

Explanation:

Greenhouse gasses in Earth's atmosphere affect Earth's temperature by making it hotter. Greenhouse gasses make the Earth warmer by trapping heat. You can think of greenhouse gasses as Earth's blanket.

5 0
3 years ago
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The exhaust gas from an automobile contains 3% by volume of carbon monoxide (CO). Express this concentration in mg/m3 at 25oC an
ser-zykov [4K]

Answer:

24540\frac{mg}{m^3}

Explanation:

Hello,

In this case, since the 3% by volume is represented as:

\frac{3L\ CO}{L\ gas}

By using the ideal gas equation we compute the density of CO:

\rho =\frac{MP}{RT} =\frac{28g/mol*1atm}{0.082\frac{atm*L}{mol*K}*298K}= 0.818g/L

Then we apply the conversion factors as follows:

=\frac{3L\ CO}{100L\ gas}*\frac{0.818g\ CO}{1L\ CO} *\frac{1000mg\ CO}{1g\ CO} *\frac{1000L\ gas}{1m^3\ gas} \\\\=24540\frac{mg}{m^3}

Regards.

4 0
4 years ago
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