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astra-53 [7]
3 years ago
12

What is the oxidation number of tin (Sn) in the compound Na2SnO2? A. -2 B. 0 C. +2 D. +3

Chemistry
2 answers:
Svetllana [295]3 years ago
8 0

Answer: Option (C) is the correct answer.

Explanation:

It is known that oxidation number of sodium is +1 and the oxidation number of oxygen is -2.

Let the oxidation number of tin (Sn) is x.

Therefore, calculate the oxidation number of tin in the given formula as follows.

                              Na_{2}SnO_{2}

       = (2 \times oxidation number of Na) + Oxidation number of Sn + (2 \times oxidation number of O)

        = (2 \times +1) + x + (2 \times (-2))

So,         2 + x - 4 = 0

therefore,          x = +2

Thus, we can conclude that the oxidation number of tin (Sn) in the compound Na_{2}SnO_{2} is +2.

Allisa [31]3 years ago
7 0

O.N. of Na = +1

O.N. of O = -2

Let, O.N. of Tin = x

1*2 + x + -2*2 = 0

2+x-4 = 0

x-2 = 0

x = 2

SO OPTION C IS YOUR ANSWER......

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timama [110]

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36. Dimensional Analysis: A useful way to convert units using multiplication & division *Always start with what you are give
ollegr [7]

Answer:

A) 7.9 x 10⁶ inches

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C) 2.8 x 10³ inches/ min

D) 1.2 x 10⁻⁴ mm

Explanation:

A) Since 39.37 inches = 1 m, you can convert meters to inches by multiplying by the conversion factor (39.37 inches /  1 m).

Notice that if 39.37 inches = 1 m then 39.37 inches / 1 m = 1. That means that when you multiply by a conversion factor, you are only changing units since it is the same as multiplying by 1 :

2.0 x 10⁵ m * (39.37 inches /  1 m) = 7.9 x 10⁶ inches

B) Conversion factors : (2.205 pounds / 1 kg) and (453.59 g / 1 pound), because 2.205 pounds = 1 kg and 1 pound = 453.59 g. Then:

1.004 kg * ( 2.205 pounds / 1 kg) * ( 453.59 g / 1 pound) = 1004 g

C) Conversion factor: (39.37 inches / 1 m) and (60 s / 1 min)

1.2 m/s * (39.37 inches / 1 m) * ( 60 s / 1 min) = 2.8 x 10³ inches/ min

D)Converison factor ( 1 mm / 1 x 10⁶ nm):

120 nm (1 mm /  1 x 10⁶ nm) = 1.2 x 10⁻⁴ mm

3 0
3 years ago
Read 2 more answers
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