Question

What is the oxidation number of tin (Sn) in the compound Na2SnO2? A. -2 B. 0 C. +2 D. +3

Answer 1

Answer: Option (C) is the correct answer.

Explanation:

It is known that oxidation number of sodium is +1 and the oxidation number of oxygen is -2.

Let the oxidation number of tin (Sn) is x.

Therefore, calculate the oxidation number of tin in the given formula as follows.

                              $Na_{2}SnO_{2}$

       = (2 \times oxidation number of Na) + Oxidation number of Sn + (2 \times oxidation number of O)

        = $(2 \times +1) + x + (2 \times (-2))$

So,         2 + x - 4 = 0

therefore,          x = +2

Thus, we can conclude that the oxidation number of tin (Sn) in the compound $Na_{2}SnO_{2}$ is +2.

Answer 2

O.N. of Na = +1

O.N. of O = -2

Let, O.N. of Tin = x

1*2 + x + -2*2 = 0

2+x-4 = 0

x-2 = 0

x = 2

SO OPTION C IS YOUR ANSWER......