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astra-53 [7]
3 years ago
12

What is the oxidation number of tin (Sn) in the compound Na2SnO2? A. -2 B. 0 C. +2 D. +3

Chemistry
2 answers:
Svetllana [295]3 years ago
8 0

Answer: Option (C) is the correct answer.

Explanation:

It is known that oxidation number of sodium is +1 and the oxidation number of oxygen is -2.

Let the oxidation number of tin (Sn) is x.

Therefore, calculate the oxidation number of tin in the given formula as follows.

                              Na_{2}SnO_{2}

       = (2 \times oxidation number of Na) + Oxidation number of Sn + (2 \times oxidation number of O)

        = (2 \times +1) + x + (2 \times (-2))

So,         2 + x - 4 = 0

therefore,          x = +2

Thus, we can conclude that the oxidation number of tin (Sn) in the compound Na_{2}SnO_{2} is +2.

Allisa [31]3 years ago
7 0

O.N. of Na = +1

O.N. of O = -2

Let, O.N. of Tin = x

1*2 + x + -2*2 = 0

2+x-4 = 0

x-2 = 0

x = 2

SO OPTION C IS YOUR ANSWER......

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Answer:

234

Explanation:

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3 years ago
A student ran the following reaction in the laboratory at 671 K: 2NH3(g) N2(g) + 3H2(g) When she introduced 7.33×10-2 moles of N
vaieri [72.5K]

Answer:

Kc = 8.05x10⁻³

Explanation:

This is the equilibrium:

                 2NH₃(g)   ⇄     N₂(g)     +     3H₂(g)

Initially       0.0733

React         0.0733α          α/2                3/2α

Eq     0.0733 - 0.0733α    α/2                0.103

We introduced 0.0733 moles of ammonia, initially. So in the reaction "α" amount react, as the ratio is 2:1, and 2:3, we can know the moles that formed products.

Now we were told that in equilibrum we have a [H₂] of 0.103, so this data can help us to calculate α.

3/2α = 0.103

α = 0.103 . 2/3 ⇒ 0.0686

So, concentration in equilibrium are

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N₂ = 0.0686/2 = 0.0343

So this moles, are in a volume of 1L, so they are molar concentrations.

Let's make Kc expression:

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3 0
3 years ago
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Ne4ueva [31]

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Ua/Ub= √(Mb/Ma)

Where Ua/Ub is the ratio of velocity of hydrogen to carbon dioxide and Ma is the molecular mass of hydrogen gas= 2

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Ua/Ub = 4.69

Therefore the ratio of velocity of hydrogen gas to carbon dioxide = 1:4.69

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8 0
3 years ago
The Ostwald process is used commercially to produce nitric acid, which is, in turn, used in many modern chemical processes. In t
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Answer:

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Explanation:

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Step 1: Determine the balanced chemical equation for the chemical reaction.

The balanced chemical equation is already given.

Step 2: Convert all given information into moles (through the use of molar mass as a conversion factor).

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x = (1.9831 * 6 ) / 5

x = 2.37972 moles

Mass of H2O = Molar mass * Molar mass

Mass = 2.7972 * 18

Mass =  42.8g

6 0
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