Hey there!:
Molar mass MgCl2 = 95.211 g/mol
Volume of solution in liters:
570.0 mL / 1000 => 0.57 L
Number of moles:
n = M * V
n = 2.00 * 0.57 => 1.14 moles of MgCl2
Therefore:
1 mol MgCl2 --------------- 95.211 g
1.14 moles MgCl2 ---------- ??
mass of MgCl2 = 1.14 * 95.211
mass of MgCl2 = 108.54 g
Hope that helps!
Answer:
6.88 × 10^-3mol
Explanation:
Molarity = number of moles (n) ÷ volume (V)
According to this question, there in 27.5 mL of 0.250 M KOH, the number of moles of KOH can, therefore, be calculated as follows:
number of moles = molarity × volume
Volume of KOH = 27.5mL = 27.5/1000
= 0.0275L
n = 0.0275 × 0.250
n = 0.006875 mol
n = 6.88 × 10^-3mol
Look up the answer online and look u the steps on how to do it as well it will help
Answer:
The answer is C
Explanation:
If we assume the sum of energy that could be obtained by absolutely transforming a unit of length, m. It is compared to the speed of light in this connection. In this case, the whole mass of the electron becomes force. In this, depending on the relation of Einstein, each electron can generate 510 keV, which is why only the option of "c" is right.
