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Pavel [41]
3 years ago
12

The set of independent variables of a function is the

Mathematics
2 answers:
galben [10]3 years ago
6 0
The answer is domain. hope this helps...

VLD [36.1K]3 years ago
5 0

Domain Is The Answer

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Write the standard equation of the circle with the given Center and radius:
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9514 1404 393

Answer:

  B.  (x +4)² +(y +5)² = 64

Step-by-step explanation:

The equation for a circle with center (h, k) and radius r is ...

  (x -h)² +(y -k)² = r²

Filling in your given values, you have ...

  (x -(-4))² +(y -(-5))² = 8²

Simplifying, you get ...

  (x +4)² +(y +5)² = 64 . . . . . . . matches choice B

_____

<em>Additional comment</em>

As you learn more different "standard form" equations, it may be helpful to keep a list, along with reminders of what the variables stand for and how the equation is used.

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2 years ago
If x=6 find the value of x/2
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6/2=3

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3 years ago
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Is x = 1/2 a solution of 6 x − 8 = −5 ?
Igoryamba

Answer:

Yes

Step-by-step explanation:

When we solve it we get 0.5 which is 1/2 in fraction from

7 0
3 years ago
18. One month, the Taylor family had cash receipts of $876.16. Their excess of cash receipts above cash payments was $56.14. Wha
Valentin [98]

$820.02

Step-by-step explanation:

Since the Taylor family had cash receipts of $876.16 and their excess of cash receipts above cash payments was $56.14.

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6 0
2 years ago
X³ by a³ + a³by x³=p x³by a³- a³by ³=q eliminate x
sasho [114]

Answer:

Step-by-step explanation:

\frac{x^3}{a^3} +\frac{a^3}{x^3} =p\\\frac{x^3}{a^3} -\frac{a^3}{x^3} =q\\adding\\2\frac{x^3}{a^3} =p+q\\\frac{x^3}{a^3} =\frac{p+q}{2} \\substitute~in~first\\\frac{p+q}{2} +\frac{2}{p+q} =p\\\frac{(p+q)^2+4}{2(p+q)} =p\\(p+q)^2+4=2p(p+q)\\p^2+q^2+2pq+4-2p^2-2pq=0\\q^2-p^2+4=0\\q^2=p^2-4

6 0
2 years ago
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