D = sqrt(3s^2) where s is the length of the side. Solving for s,
<span>3s^2 = d^2 iff </span>
<span>s^2 = d^2 / 3 iff </span>
<span>s = sqrt(d^2 / 3) </span>
<span>= d / sqrt(3) or d sqrt(3) / 3 </span>
<span>Surface area of the cube = 6 s^2. Thus, </span>
<span>A = 6 (d / sqrt(3))^2 </span>
<span>= 6d^2 / 3 </span>
<span>= 2d^2 </span>
<span>Volume = s^3. Thus, </span>
<span>V = (d / sqrt(3))^3 </span>
<span>= d^3 / 3sqrt(3) </span>
<span>= d^3 sqrt(3) / 9</span>
For the first question, use slip and slide or the box method to get (x-2)(2x-3)
Do the same for the second question to get (3x-4)(x+1)
X/49 = 21/x
x^2 = 21(49) = 1029
x = √1029 = 32.1
x = 32.1
A-b
difference means subtract
